Part B A solution of rubbing alcohol is 71.9 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 84.8 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. • View Available Hint(s) ? Milliliters of isopropanol = mL Submit Part C How many liters of a 3.35 M K2SO4 solution are needed to provide 97.5 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures. • View Available Hint(s) 国

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter10: Solutions
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Problem 68QAP: Consider two solutions at a certain temperature. Solution X has a nonelectrolyte as a solute and an...
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Part B
A solution of rubbing alcohol is 71.9 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 84.8 mL sample of the rubbing alcohol solution?
Express your answer to three significant figures.
• View Available Hint(s)
?
Milliliters of isopropanol =
mL
Submit
▼
Part C
How many liters of a 3.35 M K2SO4 solution are needed to provide 97.5 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L.
Express your answer to three significant figures.
• View Available Hint(s)
?
Volume of K2 SO4 =
L
Submit
國
Transcribed Image Text:Part B A solution of rubbing alcohol is 71.9 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 84.8 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. • View Available Hint(s) ? Milliliters of isopropanol = mL Submit ▼ Part C How many liters of a 3.35 M K2SO4 solution are needed to provide 97.5 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures. • View Available Hint(s) ? Volume of K2 SO4 = L Submit 國
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