main.pyLoad default template...1 # Split input into 2 parts: name and age2 parts = input ().split()name = parts [0]4 while name != '-1':# FIXME: The following line will throw ValueError exception.Insert try/except blocks to catch the exception.6#3age = int (parts [1]) + 1print ('{} {}'.format (name, age))10# Get next lineparts = input ().split()name = parts[@]1112 The given program reads a list of single-word first names and ages (ending with-1), and outputs that list with the age incremented. Theprogram fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try andexcept blocks to catch the ValueError exception and output 0 for the age.Ex: If the input is:Lee 18Lua 21Mary Beth 19Stu 33-1then the output is:Lee 19Lua 22Mary 0Stu 34

parts = input().split()name = parts[0]while name != '-1': try: age = int(parts[1]) + 1…

parts: name and age 1 # Split input into 2 parts = input ().split() parts[@] 3 name = 4 while name != '-1': # FIXME: The following Line will throw VatueError exception. Insert try/except blocks to catch the exception. int (parts [1]) + 1 23 7 age %3D print ('{} {}'.format (name, age)) 9. # Get next line parts = input ().split() parts[8] 10 11 12 name =

parts: name and age 1 # Split input into 2 parts = input ().split() parts[@] 3 name = 4 while name != '-1': # FIXME: The following Line will throw VatueError exception. Insert try/except blocks to catch the exception. int (parts [1]) + 1 23 7 age %3D print ('{} {}'.format (name, age)) 9. # Get next line parts = input ().split() parts[8] 10 11 12 name =

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter14: Exception Handling

Section: Chapter Questions

Problem 1PE

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The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 code name = ()age = ()parts = input().split()name = parts[0]while name != '-1':# FIXME: The following line will throw ValueError exception.# Insert try/except blocks to catch the exception.age = int(parts[1]) + 1print('{} {}'.format(name, age))# Get next lineparts = input().split()name = parts[0]
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 √
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18Lua 21Mary Beth 19Stu 33-1 then the output is: Lee 19Lua 22Mary 0Stu 34 #include <string>#include <iostream> using namespace std; int main(int argc, char* argv[]) { string inputName; int age; // Set exception mask for cin stream cin.exceptions(ios::failbit); cin >> inputName; while(inputName != "-1") { // FIXME: The following line will throw an ios_base::failure. // Insert a try/catch statement to catch the exception. // Clear cin's failbit to put cin in a useable state. cin >> age; cout << inputName << " " << (age + 1) << endl;…
This is in C++ The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. #include <string>#include <iostream> using namespace std; int main(int argc, char* argv[]) {string inputName;int age;// Set exception mask for cin streamcin.exceptions(ios::failbit); cin >> inputName;while(inputName != "-1") {// FIXME: The following line will throw an ios_base::failure.// Insert a try/catch statement to catch the exception.// Clear cin's failbit to put cin in a useable state.cin >> age;cout << inputName << " " << (age + 1) << endl; cin >> inputName;}return 0;} EX INPUT Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 EX OUTPUT Lee 19 Lua 22 Mary 0 Stu 34 Thanks!!
Given a list named my_list. my_list=[10,20,30,40,60,100,2,5] Write a python program that takes the position as an input from the user and prints the element of that position from the list. If the user’s input position is not in the range, return an exception stating “Index out of range”. Make sure your program always prints “Program ended” at the end, no matter what happens. ============================= Hint: Use finally block ============================= Example 1:Input:1Output:20Program ended ============================= Example 2:Input:10Output:Index out of range.Program ended what is the solution of this in python programming?
USING PYTHON: Given a list of 10 names, complete the program that outputs the name specified by the list index entered by the user. Use a try block to output the name and an except block to catch any IndexError. Output the message from the exception object if an IndexError is caught. Output the first element in the list if the invalid index is negative or the last element if the invalid index is positive. Note: Python allows using a negative index to access a list, as long as the magnitude of the index is smaller than the size of the list. Ex: If the input of the program is: 5 the program outputs: Name: Jane Ex: If the input of the program is: 12 the program outputs: Exception! list index out of range The closest name is: Johnny Ex: If the input of the program is: -2 the program outputs: Name: Tyrese Ex: If the input of the program is: -15 the program outputs: Exception! list index out of range The closest name is: Ryley CODE: names = ['Ryley', 'Edan', 'Reagan', 'Henry', 'Caius',…
Complete a program that reads a vector index as input and outputs the element of a vector of 10 names at the index specified by the input. Use a try block to output the name and a catch block to catch any out_of_range exceptions. When an out_of_range exception is caught, output the message from the exception object and the first element in the vector if the index is negative or the last element if the index is greater than the size of the vector. Hint: Format the exception outputs using the what() function from the exception object. Do not hard code the exception messages. Ex: If the input of the program is: 5 the program outputs: Jane Ex: If the input of the program is: 12 the program outputs: Exception! vector::_M_range_check: __n (which is 12) >= this->size() (which is 10) The closest name is: Johnny Ex: If the input of the program is: -2 the program outputs: Exception! vector::_M_range_check: __n (which is 18446744073709551614) >= this->size() (which is 10) The closest…
Given a main program that searches for the ID or the name of a student from a dictionary, complete the find_ID() and the find_name() functions that return the corresponding information of a student. Then, insert a try/except statement in main() to catch any exceptions thrown by find_ID() or find_name(), and output the exception message. Each entry of the dictionary contains the name (key) and the ID (value) of a student. Function find_ID() takes two parameters, a student's name and a dictionary. Function find_ID() returns the ID associated with the student's name if the name is in the dictionary. Otherwise, the function throws a custom exception type, StudentInfoError, with the message "Student ID not found for studentName", where studentName is the name of the student. Function find_name() takes two parameters, a student's ID and a dictionary. Function find_name() returns the name associated with the student's ID if the ID is in the dictionary. Otherwise, the function throws a custom…
Given a main program that searches for the ID or the name of a student from a dictionary, complete the find_ID() and the find_name() functions that return the corresponding information of a student. Then, insert a try/except statement in main() to catch any exceptions thrown by find_ID() or find_name(), and output the exception message. Each entry of the dictionary contains the name (key) and the ID (value) of a student. Function find_ID() takes two parameters, a student's name and a dictionary. Function find_ID() returns the ID associated with the student's name if the name is in the dictionary. Otherwise, the function throws a custom exception type, StudentInfoError, with the message "Student ID not found for studentName", where studentName is the name of the student. Function find_name() takes two parameters, a student's ID and a dictionary. Function find_name() returns the name associated with the student's ID if the ID is in the dictionary. Otherwise, the function throws a custom…
Given a main program that searches for the ID or the name of a student from a dictionary, complete the find_ID() and the find_name() functions that return the corresponding information of a student. Then, insert a try/except statement in main() to catch any exceptions thrown by find_ID() or find_name(), and output the exception message. Each entry of the dictionary contains the name (key) and the ID (value) of a student. Function find_ID() takes two parameters, a student's name and a dictionary. Function find_ID() returns the ID associated with the student's name if the name is in the dictionary. Otherwise, the function throws a custom exception type, StudentInfoError, with the message "Student ID not found for studentName", where studentName is the name of the student. Function find_name() takes two parameters, a student's ID and a dictionary. Function find_name() returns the name associated with the student's ID if the ID is in the dictionary. Otherwise, the function throws a custom…
Given a main program that searches for the ID or the name of a student from a dictionary, complete the find_ID() and the find_name() functions that return the corresponding information of a student. Then, insert a try/except statement in main() to catch any exceptions thrown by find_ID() or find_name(), and output the exception message. Each entry of the dictionary contains the name (key) and the ID (value) of a student. Function find_ID() takes two parameters, a student's name and a dictionary. Function find_ID() returns the ID associated with the student's name if the name is in the dictionary. Otherwise, the function throws a custom exception type, StudentInfoError, with the message "Student ID not found for studentName", where studentName is the name of the student. Function find_name() takes two parameters, a student's ID and a dictionary. Function find_name() returns the name associated with the student's ID if the ID is in the dictionary. Otherwise, the function throws a custom…