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Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is homozygous recessive for gene c, and heterozygous for gene I, is crossed with a father chicken, who is heterozygous for the pigment gene, and heterozygous for gene I. Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers. • The inhibitor gene (I) will prevent expression of pigmented chicken feathers. Here is a DihybridCrossReview.pdf reviewing the FOIL method for determining gametes and performing a dihybrid cross if you need a refresher. A) What are the potential genotypes of the gametes produced by the mother for these two genes? • Use the letters C, c, I, and i for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabatize your haplotypes, e.g. Ab, not bA. B) What are the potential genotypes of the gametes produced by the father for these two gametes? • Use the letters C, c, I, andi for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabetize your haplotypes, e.g. Ab, not bA. C) What is the probability of one of the offspring of these two chickens having white feathers? Enter your answer as a percent, but do not include the percent symbol, e.g. 75, not 75%, 0.75, or 3/4 Report your answer to one decimal place, e.g. 66.7, not 66.66 or 66.60. D) In a population of 100 chickens, produced from the same parents, how many chickens would you expect to have pigments feathers? • Round your answer to the lowest whole number since you cannot have a partial chicken, e.g. 65.8 would round to 65, as would 65.4, 65.5.

Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is homozygous recessive for gene c, and heterozygous for gene I, is crossed with a father chicken, who is heterozygous for the pigment gene, and heterozygous for gene I. Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers. • The inhibitor gene (I) will prevent expression of pigmented chicken feathers. Here is a DihybridCrossReview.pdf reviewing the FOIL method for determining gametes and performing a dihybrid cross if you need a refresher. A) What are the potential genotypes of the gametes produced by the mother for these two genes? • Use the letters C, c, I, and i for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabatize your haplotypes, e.g. Ab, not bA. B) What are the potential genotypes of the gametes produced by the father for these two gametes? • Use the letters C, c, I, andi for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabetize your haplotypes, e.g. Ab, not bA. C) What is the probability of one of the offspring of these two chickens having white feathers? Enter your answer as a percent, but do not include the percent symbol, e.g. 75, not 75%, 0.75, or 3/4 Report your answer to one decimal place, e.g. 66.7, not 66.66 or 66.60. D) In a population of 100 chickens, produced from the same parents, how many chickens would you expect to have pigments feathers? • Round your answer to the lowest whole number since you cannot have a partial chicken, e.g. 65.8 would round to 65, as would 65.4, 65.5.

Biology (MindTap Course List)
Biology (MindTap Course List)
11th Edition
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Chapter11: The Basic Principles Of Heredity
Section: Chapter Questions
Problem 10TYU: A walnut comb rooster is mated to three hens. Hen A, which has a walnut comb, has offspring in the...
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Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is homozygous recessive for gene c, and heterozygous for gene I, is crossed with a father chicken, who is heterozygous for the pigment gene, and heterozygous for gene I. Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers. • The inhibitor gene (I) will prevent expression of pigmented chicken feathers. Here is a DihybridCrossReview.pdf reviewing the FOIL method for determining gametes and performing a dihybrid cross if you need a refresher. A) What are the potential genotypes of the gametes produced by the mother for these two genes? • Use the letters C, c, I, and i for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabatize your haplotypes, e.g. Ab, not bA. B) What are the potential genotypes of the gametes produced by the father for these two gametes? • Use the letters C, c, I, andi for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabetize your haplotypes, e.g. Ab, not bA. C) What is the probability of one of the offspring of these two chickens having white feathers? Enter your answer as a percent, but do not include the percent symbol, e.g. 75, not 75%, 0.75, or 3/4 Report your answer to one decimal place, e.g. 66.7, not 66.66 or 66.60. D) In a population of 100 chickens, produced from the same parents, how many chickens would you expect to have pigments feathers? • Round your answer to the lowest whole number since you cannot have a partial chicken, e.g. 65.8 would round to 65, as would 65.4, 65.5.
Transcribed Image Text:Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is homozygous recessive for gene c, and heterozygous for gene I, is crossed with a father chicken, who is heterozygous for the pigment gene, and heterozygous for gene I. Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers. • The inhibitor gene (I) will prevent expression of pigmented chicken feathers. Here is a DihybridCrossReview.pdf reviewing the FOIL method for determining gametes and performing a dihybrid cross if you need a refresher. A) What are the potential genotypes of the gametes produced by the mother for these two genes? • Use the letters C, c, I, and i for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabatize your haplotypes, e.g. Ab, not bA. B) What are the potential genotypes of the gametes produced by the father for these two gametes? • Use the letters C, c, I, andi for the genes. C is for color and I is for inhibitor • Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. • Do not write a sentence. • Do not list duplicate haplotypes. Alphabetize your haplotypes, e.g. Ab, not bA. C) What is the probability of one of the offspring of these two chickens having white feathers? Enter your answer as a percent, but do not include the percent symbol, e.g. 75, not 75%, 0.75, or 3/4 Report your answer to one decimal place, e.g. 66.7, not 66.66 or 66.60. D) In a population of 100 chickens, produced from the same parents, how many chickens would you expect to have pigments feathers? • Round your answer to the lowest whole number since you cannot have a partial chicken, e.g. 65.8 would round to 65, as would 65.4, 65.5.
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