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Please describe the key characteristics of the H-NMR and 13C-NMR spectra.
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- The infrared spectrum of the compound with the mass spectrum shown below lacks any significant absorption above 3000 cm-1. There is a prominent peak near 1740 cm-1 and another strong peak near 1200 cm-1. Propose a structure consistent with the data.A 13C NMR spectrum is shown below. Match the spectrum with the proper structure.Organic chemistry 2: from the attached NMR spectrum what can be the proposed molecule that corresponds to the spectrum. Please discuss how how you arrived at the identity of the compound.
- Look at NMR and answer #2,3 and 4Complete the following answer using the data provided here: Molecular formula: C4H8O2 Important IR data (cm-1): 3280 (broad); 2980-2730 (many); 1690; 1254 All 1H NMR data (ppm, splitting, integration): 11.0 ppm (s), 1; 2.57 ppm (m), 1; 1.07 ppm (d), 6 1. Sketch out a 1H NMR spectrum showing peak locations and peak splitting on a ppm scale for the data provided above. Include the data labels above in your spectrum, but do not show integration lines. 2. draw the most proper line bond structure for the data given aboveConsider the product below a) Predict the 1H NMR spectrum for this molecule. Predict the multiplicity, integration and relative ppm b) Predict the 13C NMR spectrum and DEPT spectra. Use (+) for positivesignals, (-) for negative signals, and (X) for no signal in the DEPT NMR spectra.
- From the spectra, determine the structure of the molecule.Remember to ignore the triad in the 13 C NMR spectrum at 77 ppm thatcomes from the NMR solvent1) Propose the structures for the following 1H and 13C NMR spectra. a) Molecular Formula: C5H10O2 1H-NMR, CDCl3 Solvent, Molecular Formula: C5H10O2 13C-NMR, CDCl3 Solvent, Molecular Formula: C5H10O2 in the picturesDraw the structure of C10H18O2 which is consistent with the 13C NMR data below. Thepeak appearing at 14 ppm is actually two very close peaks.
- The NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 . The 1H and 13C peaks are also listedbelow. Provide a full analysis of the NMR spectra for compound 1. correct assignment of NMR spectra of both 13C spectra. correct rationalisation of 13C spectrum1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).13C NMR (101 MHz, CDCl3) δ 160.79, 154.09, 143.43, 131.85, 127.87, 124.44, 118.86,116.94, 116.74.Note: There are two carbon peaks in the 13C spectrum that are so close together that they are not differentiable at the resolution in this experiment. you should be able to assign these peaks to one of two carbon atoms in 1.I have an NMR spectrum. There are 5 peaks. There is a doublet at 9.6 ppm (integrates to 2H) where aldehydes usually arise, don't know why there is a doublet. There is another doublet at 6.8 ppm, again integrating to 2H. There is a singlet at 4.5 ppm, integrating to 1H. There is a quartet at 3.4 ppm integrating to 2H, and lastly there is triplet at 1.2 ppm integrating to 3H. i recofnize the ethyl group but don't understand the peak at 9.6 unless it is not an aldehyde.39. provide the answer ASap