Please use the values in the resources listed below instead of the textbook values. Calculate the equilibrium concentration (in M) of Ni2+ in a 0.71 M solution of Ni(CN),² (K = 1.7x 1030) %D

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Please use the values in the resources listed below instead of the textbook values.
Calculate the equilibrium concentration (in M) of Ni2+ in a 0.71 M solution of Ni(CN),2-. (K, = 1.7x 1030)
%D
4
4.0
t.
Supporting Materials
Periodic Table
Constants and
Supplemental Data
Factors
Additional Materials
Section 15.3
Transcribed Image Text:Safari File Edit View History Bookmarks Window Help <> A webassign.net Course:.. W. CHM 152... Cengage. * Mind Tap.. Rapidlde... Business... Please use the values in the resources listed below instead of the textbook values. Calculate the equilibrium concentration (in M) of Ni2+ in a 0.71 M solution of Ni(CN),2-. (K, = 1.7x 1030) %D 4 4.0 t. Supporting Materials Periodic Table Constants and Supplemental Data Factors Additional Materials Section 15.3
Expert Solution
Step 1

Given : Concentration of Ni(CN)42- = 0.71 M

And Kf of Ni(CN)42- = 1.7 X 1030 

The formation reaction of Ni(CN)42- complex can be written as,

=> Ni2+ (aq) + 4 CN- (aq) -------> Ni(CN)42- (aq)                                Kf = 1.7 X 1030 

 

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