What torque applied to the cylinder of prob 1220 will raise the weight with an acceleration of 13 ft/sec? What will be the total bearing reaction? Cont:96.6-T 9a – Eq.2%3DMultiply Eq.2 by 3:289.8-37T = 27a%3D3T = 45aAdding the two equation:289.872a%3Da = 4.03 rad/secSubst. a from (1)3T = 45aT= 60.5 lbEF = 0R= 322 +60.5%3D%3DR382.5 lb Problem 1220: A weight of 96.6 Ib is fastened to a cordwhich is wrapped around a solid cylinder of 3 ft.radius weighing 322 Ib. The cylinder rotates about itshorizontal controidal axis. Compute the angularacceleration and the tension in the cord; also thetotal bearing reaction.W = 322 Ib322Ī= ½Mr² = ½(3)²32.2,%3D3'I = 45lb – ft. sec?%3DΣΜ-Ια3T = 45a – Eq. 1%3DΣΧa-g96. 696.6 - Т -(За)32.2a = a96 6-T= 3(3a)%3D

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plem 1220: A weight of 96.6 lb is fastened to a cord nich is wrapped around a solid cylinder of 3 ft. dius weighing 322 Ib. The cylinder rotates about its prizontal controidal axis. Compute the angular cceleration and the tension in the cord; also the otal bearing reaction. W = 322 lb ( 322)

plem 1220: A weight of 96.6 lb is fastened to a cord nich is wrapped around a solid cylinder of 3 ft. dius weighing 322 Ib. The cylinder rotates about its prizontal controidal axis. Compute the angular cceleration and the tension in the cord; also the otal bearing reaction. W = 322 lb ( 322)

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter13: Rotation Ii: A Conservation Approach

Section: Chapter Questions

Problem 6PQ: Rotational Inertia Problems 5 and 6 are paired. 5. N A system consists of four boxes modeled as...

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Concept explainers

Angular speed, acceleration and displacement

Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

Angular Position

Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.

Question

What torque applied to the cylinder of prob 1220 will raise the weight with an acceleration of 13 ft/sec? What will be the total bearing reaction?

Cont:
96.6-T 9a – Eq.2
%3D
Multiply Eq.2 by 3:
289.8-37T = 27a
%3D
3T = 45a
Adding the two equation:
289.8
72a
%3D
a = 4.03 rad/sec
Subst. a from (1)
3T = 45a
T= 60.5 lb
EF = 0
R= 322 +60.5
%3D
%3D
R
382.5 lb

Problem 1220: A weight of 96.6 Ib is fastened to a cord
which is wrapped around a solid cylinder of 3 ft.
radius weighing 322 Ib. The cylinder rotates about its
horizontal controidal axis. Compute the angular
acceleration and the tension in the cord; also the
total bearing reaction.
W = 322 Ib
322
Ī= ½Mr² = ½
(3)²
32.2,
%3D
3'
I = 45lb – ft. sec?
%3D
ΣΜ-Ια
3T = 45a – Eq. 1
%3D
ΣΧ
a
-
g
96. 6
96.6 - Т -
(За)
32.2
a = a
96 6-T= 3(3a)
%3D

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