Pproducts PReactants PH₂ PIZ hp- hp= (PHI)2 1.34-10 = (0.45 +0) (1.17+p) t1.51-212 1.34-10--/151-701² (1 Dr. Dahm is attempting to store a sample of HI. Little does he realize that there exists an equilibrium between HI, I, and H₂. If he starts with an initial pressure of HI of 1.51 atm, H₂ of 0.45 atm and I₂ of 1.17 atm find the pressures at equilibrium. K for this reaction is 1.34 10¹ calculate the pressure of I, and H, when the reaction comes to equilibrium. 2 HI 1.51 Initial Change-2p Equilibrium-1.51-2p - Solving Equilibrium atm H₂ + 1₂ 0.45 alm +p 045+p 1.17 QAm +P 1.17-p

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.BCP
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Question
12:56 AM Wed Nov 9
X
no
00
Chemistry
Pproducts
PReactants
PH₂ PIZ
про
1.34 10 = (0.45 +p) (1.17+p)
t1.51-2p)2
bp= (PHI)
Û Homework+23+Equilibrium+2+NB ✓
1.34-10 (1.51-2)² = (0.45 +p)(1.17+p)
x Chem+101+exam+2+2019
,
Dr. Dahm is attempting to store a sample of HI. Little does he realize that there exists an
equilibrium between HI, I, and H₂. If he starts with an initial pressure of HI of 1.51 atm, H₂
of 0.45 atm and I, of 1.17 atm find the pressures at equilibrium. K for this reaction is 1.34
10¹ calculate the pressure of I, and H₂ when the reaction comes to equilibrium.
X=-3± √5²-4ac
2a
P= -2.43± √(243) ²-4 (0.464)(0.221)
2(0.464)
P. -2.43± √5.9044-0.410176
0.134 (28²) -0.5265-5p+1-2p+p²
0.3065334 053 0.80496p=0.5865+1
0.536p²-p²-0.88936p-1.62p+0.3055334-0.5265
-0.464p²-242936p-0.220966 -0
10.464p² +243p +0.2211-0
a
0.928
P= -243±2.344 -0.085917
0.928
0.928
P= -0.092583 atm/
2 HI
1.5)
Initial
Change-2p
Equilibrium-1.51-2p
atm
Solving Equilibrium
x Argument+Essay+Final+...
2N₂
N₂ + O₂
H₂
0.45
PH₂ 0.45aton-P
-0.45-(-0.092583)
= 0.542583 atm
Pressure He=0.54
alm
+p
0.45+p
PIZ-1.17am-p
Pressure Ie 1.26 alm
1.17-(-0.092583)
=1.262583 atm
+
T
2N₂O
1₂
1.17
atm
+P
1.17+p
'
Dr. Dahm wants to make N₂O so he reacts N₂ with O₂ to give N₂O. Unfortunately this is an
equilibrium process that has a K of 2.0 10. If he starts with a pressure of 1.57 for N, and
1.68 for O, calculate the pressure of N₂O at equilibrium.
x Homework+23+Equili... A
53%
Transcribed Image Text:12:56 AM Wed Nov 9 X no 00 Chemistry Pproducts PReactants PH₂ PIZ про 1.34 10 = (0.45 +p) (1.17+p) t1.51-2p)2 bp= (PHI) Û Homework+23+Equilibrium+2+NB ✓ 1.34-10 (1.51-2)² = (0.45 +p)(1.17+p) x Chem+101+exam+2+2019 , Dr. Dahm is attempting to store a sample of HI. Little does he realize that there exists an equilibrium between HI, I, and H₂. If he starts with an initial pressure of HI of 1.51 atm, H₂ of 0.45 atm and I, of 1.17 atm find the pressures at equilibrium. K for this reaction is 1.34 10¹ calculate the pressure of I, and H₂ when the reaction comes to equilibrium. X=-3± √5²-4ac 2a P= -2.43± √(243) ²-4 (0.464)(0.221) 2(0.464) P. -2.43± √5.9044-0.410176 0.134 (28²) -0.5265-5p+1-2p+p² 0.3065334 053 0.80496p=0.5865+1 0.536p²-p²-0.88936p-1.62p+0.3055334-0.5265 -0.464p²-242936p-0.220966 -0 10.464p² +243p +0.2211-0 a 0.928 P= -243±2.344 -0.085917 0.928 0.928 P= -0.092583 atm/ 2 HI 1.5) Initial Change-2p Equilibrium-1.51-2p atm Solving Equilibrium x Argument+Essay+Final+... 2N₂ N₂ + O₂ H₂ 0.45 PH₂ 0.45aton-P -0.45-(-0.092583) = 0.542583 atm Pressure He=0.54 alm +p 0.45+p PIZ-1.17am-p Pressure Ie 1.26 alm 1.17-(-0.092583) =1.262583 atm + T 2N₂O 1₂ 1.17 atm +P 1.17+p ' Dr. Dahm wants to make N₂O so he reacts N₂ with O₂ to give N₂O. Unfortunately this is an equilibrium process that has a K of 2.0 10. If he starts with a pressure of 1.57 for N, and 1.68 for O, calculate the pressure of N₂O at equilibrium. x Homework+23+Equili... A 53%
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