The give reaction is C6H12O6 (s) + O₂(g) → CO₂ (g) + H₂O (1) Asrxnnxsº (products)->nxsº (reactants) = s° CO, (g) + s° H2O (U) -[ s° C%H_2O6 (s) + s° Oz(g)] = (213.7 J/mol-K+ 69.9 J/mol-K)-(212.0 J/mol-K+205.1 J/mol-K) = -133.5 J/mol-K Ans: the change in entropy, AS system of the given reaction is = -133.5 J/mol-K
The give reaction is C6H12O6 (s) + O₂(g) → CO₂ (g) + H₂O (1) Asrxnnxsº (products)->nxsº (reactants) = s° CO, (g) + s° H2O (U) -[ s° C%H_2O6 (s) + s° Oz(g)] = (213.7 J/mol-K+ 69.9 J/mol-K)-(212.0 J/mol-K+205.1 J/mol-K) = -133.5 J/mol-K Ans: the change in entropy, AS system of the given reaction is = -133.5 J/mol-K
General Chemistry - Standalone book (MindTap Course List)
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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.132QP
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From the attached solution where did you get this?
= S CO2 (g) + S H2O (l) - [ S C6H12O6 (s) + S O2(g)]
= (213.7 J/mol-K + 69.9 J/mol-K) - (212.0 J/mol-K + 205.1 J/mol-K)
![The give reaction is
C6H12O6 (s) + O₂(g) → CO₂ (g) + H₂O (1)
Asº
rxn-Σ nxsº (products)-[nxs (reactants)
= s° CO, (g) + s° H,O (U) -[ s° C%H_z©% (s) +s° ©z(g)]
= (213.7 J/mol-K+ 69.9 J/mol-K)-(212.0 J/mol-K + 205.1 J/mol-K)
= -133.5 J/mol-K
Ans: the change in entropy, AS system of the given reaction is = -133.5 J/mol-K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb13aea73-b3d8-4517-8deb-3cef337bfb03%2F5127406a-79e2-4ad2-a9a3-58be0102768a%2F7aw1tl7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The give reaction is
C6H12O6 (s) + O₂(g) → CO₂ (g) + H₂O (1)
Asº
rxn-Σ nxsº (products)-[nxs (reactants)
= s° CO, (g) + s° H,O (U) -[ s° C%H_z©% (s) +s° ©z(g)]
= (213.7 J/mol-K+ 69.9 J/mol-K)-(212.0 J/mol-K + 205.1 J/mol-K)
= -133.5 J/mol-K
Ans: the change in entropy, AS system of the given reaction is = -133.5 J/mol-K
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