Please answer the exercise below 8:58cdn.fbsbx.comDoneV LAI T.1. As the sample size n increases, the sampling distribution of the means approaches a normal distribution.2. The mean of the sampling distribution of means is equal to the mean of the population.fx = μl3. The variance of the sampling distribution of means is equal to the variance of the population divided bythe sample size.0²o² =4. The standard deviation of the sampling distribution of means is equal to the standard deviation of thepopulation divided by the square root of the sample sizeσx==VnExample1:A random sample of n = 49 measurements is obtained from a population with = 192 and = 43.Describe the sampling distribution of means by computing the (a) mean of the sampling distribution ofmeans, and the (b) standard deviation of the sampling distribution of means .SOLUTION: The given are the sample size=49, population mean = 192, and population standarddeviation a = 43.a. Solve for the mean of sampling distribution of means.#₂ = μ since the population mean is 192, therefore the mean of sampling distribution of means is also 192.H₂= 192b. Solve for the standard deviation of the sampling distribution of means.0₂= m430₂=√49430₂ = 7d₂ = 6.1429 or 6.14Example 2:Samples of size n were randomly selected from the population with means and variances given below.In each case, find the mean and the variance of the sampling distribution of the means.a. n36; 44; ²5.76b. n = 45; μ = 40; a² = 5.76Solutions: a. The mean of sampling distribution of means is also 44 since the population mean is 44 (= 44).To find the variance of the sampling distribution of the means, we use oo}73765.7636= 0.16b. The mean of sampling distribution of means is also 40 since the population mean is 40 (μ-40).To find the variance of the sampling distribution of the means, we use a =oof= 15.7645of = 0.128Now it's your turn to practice.Practice ExerciseA. Samples of size n were randomly selected from the population with means and variances givenbelow. In each case, find the mean and the variance of the sampling distribution of the means.1. n = 42; μ = 25; ²= 6.252. n = 30; p = 10; ²9B. A random sample of 264 measurements is obtained from a population with = 60 and 20.Describe the sampling distribution of means by computing the (a) mean of the sampling distribution ofmeans, and the (b) standard deviation of the sampling distribution of means o.Evaluation

Question

Accepted Answer

Given:
A)
1. n=42, μ=25, σ2=6.25