practice in Southern California for houses to be built with pools in the backyard. For new homes, however, that practice may be changing, possibly as a measure to help reduce climate change. A recent study examined a random sample of 140 houses built in Southern California in the twentieth century and an independent, random sample of 81 new houses built in Southern California. The sample of twentieth century houses contained 61 houses with pools, and the sample of new houses contained 24 houses with pools.Based on this survey, can we conclude, at the 0.05 level of significance, that the proportion p1 of all Southern California twentieth century houses that were built with pools is greater than the proportion p2of all new Southern California houses that were built with pools?Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the parts below. (If necessary, consult a list of formulas.) A. Find the value of the test statistic and round to 3 or more decimal places. (I have posted a picture of an example problem and the equation to use, with the correct answer as every expert I have asked thus far has gotten this problem wrong.) B. Find the critical value at the 0.05 level of significance. (Round to three or more decimal places.) C. Can we conclude that the proportion of Southern California twentieth century houses built with pools is greater than the proportion for new homes?

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
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Chapter11: Data Analysis And Probability
Section: Chapter Questions
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In the twentieth century, it was a common practice in Southern California for houses to be built with pools in the backyard. For new homes, however, that practice may be changing, possibly as a measure to help reduce climate change. A recent study examined a random sample of 140 houses built in Southern California in the twentieth century and an independent, random sample of 81 new houses built in Southern California. The sample of twentieth century houses contained 61 houses with pools, and the sample of new houses contained 24 houses with pools.Based on this survey, can we conclude, at the 0.05 level of significance, that the proportion p1 of all Southern California twentieth century houses that were built with pools is greater than the proportion p2of all new Southern California houses that were built with pools?Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the parts below. (If necessary, consult a list of formulas.)

A. Find the value of the test statistic and round to 3 or more decimal places. (I have posted a picture of an example problem and the equation to use, with the correct answer as every expert I have asked thus far has gotten this problem wrong.)

B. Find the critical value at the 0.05 level of significance. (Round to three or more decimal places.)

C. Can we conclude that the proportion of Southern California twentieth century houses built with pools is greater than the proportion for new homes?

 

Finding the value of the test statistic
The value of this test statistic is the z-value corresponding to the sample proportion under the assumption that H is true. Here is its value.
р-р
p(1-p)
n
58
105
-0.47
0.47(1-0.47)
210
~2.392
Transcribed Image Text:Finding the value of the test statistic The value of this test statistic is the z-value corresponding to the sample proportion under the assumption that H is true. Here is its value. р-р p(1-p) n 58 105 -0.47 0.47(1-0.47) 210 ~2.392
A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 80%.
After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 80% of married couples. In a
random sample of 215 married couples who completed her program, 180 of them stayed together. Based on this sample, is there enough evidence to support
the marriage counselor's claim at the 0.05 level of significance?
Perform a one-tailed test. Then complete the parts below.
Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.)
Transcribed Image Text:A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 80%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 80% of married couples. In a random sample of 215 married couples who completed her program, 180 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.)
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