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- What is the percent magnesium hydroxide, if a sample of magnesia magma weighing 5.2430g when dissolved in 25 mL of 0.9915 N H2SO4 required 9.85 mL of 1.4102 N NaOH to titrate the excess acid? Round to 2 decimal point; Answer should be with the correct unit.How many milliliters of 0.10 M Pb(NO 3 )2 should be used to make ni(en)(h2o)4so4 10% mole excess?A solution of sulfuric acid was made by dissolving 20.0g of 98% sulfuric acid in a 250mL of water. (H2SO4 = 98.078 g/mol; H2O = 18.015 g/mol)Additional information for 35-37 What if the solution has a total volume of 262ml? 1. Express the concentration of this solution in % by weight.a. 7.3%b. 4.4%c. 8.0%d. 7.8% 2. Express the concentration in molaritya. 0.10 Mb. 2.00 Mc. 0.76 Md. 0.93 M 3. Express the concentration in normalitya. 2.0 Nb. 1.5 Nc. 1.0 Nd. 0.76 N 4. Express the concentration in molalitya. 0.80 mb. 0.77 mc. 1.00 md. 1.50 m
- What volume (in mL) of 30.0% hydrogen peroxide solution is required to provide the mass required in question 8 above? Mass=10.2g of a 30% hydrogen peroxide soltuion. Density of 30.0% H2O2 = 1.11 g/mL Answer with 3 sig figs.Dapsone tablets, labelled 50 mg has an average tablet weight of 0.6509 g. 2.0g of powdered tablets reacted (see reaction below) with 26.05 mL of 0.0506N sodium nitrite (NaNO2) solution. Determine the amount of Dapsone as a percentage of the Label Strength (or Label Claim). Report your answer to 1 decimal place. Given: Dapsone molar mass, 248.302 g/mol Dapsone structure Reaction: Sodium nitrite (NaNO2) reacts with hydrochloric acid (HCl) to generate nitrous acid (HNO2). NaNO2 + HCl ® HNO2 + NaCl Nitrous acid (HNO2) then reacts with each amino group on Dapsone, and an indicator indicates the endpoint. R-NH2 (full structure shown above) + HNO2 + HCl ® R-N2Cl + 2H2ONaOH Concentration (M): 0.09669M Trial 1: Inital Volume of NaOH: 0.55mL Final Volume of NaOH: 28.25 mL Trail 2: Intial Volume of NaOH: 18.1 mL Final Volume of NaOH: 46.1 mL Concentration of HCl Solution Subtract the initial buret reading from the end point reading. Convert the readings to liters by dividing by 1000. Solve this equation for the concentration of HCl: (CHCl) (0.01000 liters ) = (CNaOH) (volume of NaOH in liters). CNaOH is the normality of the NaOH you recorded from the bottle. Average the two HCl concentrations.
- SOLVE STEP BY STEPDO NOT USE CHATGPTMAKE THE RESOLUTION QUICKLY PLEASE 18. How many mL of hydrochloric acid are required to measure to prepare 1 L of a 0.25 M solution if the density of HCl is 1.17 g/mL and its purity is 36%? (PA of H is 1,008 amu, Cl is 35,451 amu)What volume in liters of 0.500 M H2SO4 is required to neutralize a solution prepared by dissolving 28.5 g of KOH in 250 mL of water? Group of answer choices 0.508 1.02 0.254 0.127Calculate the ksp for this hypothetical an ionic compound M2X3 (MM=288 g) if its solubility is 3.6 x 10-17 g/L.
- 6-40 What is the molarity of each solution? (a) 47 g of KCI dissolved in enough water to give 375 mL of solution (b) 82.6 g of sucrose, C12H22O11, dissolved in enough water to give 725 mL of solution (c) 9.3 g of ammonium sulfate, (NH4)2SO4 dissolved in enough water to give 2.35 L of solutionA 500 mL solution of 0.250 M NH, is required. What is the volume of 28wt \% of NH, (density = 0.899g / m * L ) required to make this solution? (a) 14.8 mL (b) 2.56 mL (c) 28.3 mL (d) 8.46 mL4. Assuming no calculation errors, why would a percent recovery > 100% or a percent recovery < 100% be obtained? Give at least one reason for each