Predicting Products Practice You do NOT need to balancing the equations this time, Туре | HgO → Hg + O2 Predicting Products Practice and Balancing Practice Predict the products and then balance. * Type of Rxn Reaction Reaction and Products HgO + Cl: → NaCl + A£NO3 → Mg + HCI → Na + Br2 → 2 Synthesis Zn + H:SO4→ KCIO; →KCI + O: NAOH + HCI→ 5 CH4 + O2 → | Ca(OH): + HNO3 → Al:(SO4)3+Ca(OH)2 → |Hz+ O2 → H:O Al:Os → Al + O2 Ch+ NaBr → NaCI+ Br2 CuCla+ H2S → Zn + CUSO4→ 10 KCIO:→KCI + O2 11 NaOH + HBr → H:O + Fe → 12 Assume you have iron) in your products | Ca(OH): + HNO3 → 13 H:O + Fe → Synthesis Na:O+CO:→ 14 | Assame you have iront) in yoar products H2+ N2→NH3 15 3. 2.

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Predicting Products Practice
You do NOT need to balancing the equations this time.
Туре
Predicting Products Practice and Balancing Practice
Predict the products and then balance.
#
Reaction and Products
Reaction
# Type of Rxn
HgO → Hg + O2
| HgO + Cl2 →
1
NaCI + AgNOs →
2
Mg + HCI →
|Na + Br2 →
3
2 Synthesis
Zn + H2SO4>
4
KCIO: >KCI + O2
NaOH + HCI→
3
CH4 + 02 →
|Ca(OH)2 + HNO» →
Al:(SO4)s+Ca(OH)2 →
H2 + O2→ H20
Al:O3 → Al + O2
8
5
Ch+ NaBr → NaCl + Bra
9
CuCla+ H2S →
Zn + CuSO4
10
KCIO3 →KCI + 02
11
NAOH + HBr →
H2O + Fe >
12
Assume you have ironl) in SMr products
Ca(OH)2 + HNO3 →
13
Н.О + Fe >
Synthesis Na:0 + CO2 →
14
Assume you have iron(l) in your products
H2 + N2 →NH3
15
Transcribed Image Text:Predicting Products Practice You do NOT need to balancing the equations this time. Туре Predicting Products Practice and Balancing Practice Predict the products and then balance. # Reaction and Products Reaction # Type of Rxn HgO → Hg + O2 | HgO + Cl2 → 1 NaCI + AgNOs → 2 Mg + HCI → |Na + Br2 → 3 2 Synthesis Zn + H2SO4> 4 KCIO: >KCI + O2 NaOH + HCI→ 3 CH4 + 02 → |Ca(OH)2 + HNO» → Al:(SO4)s+Ca(OH)2 → H2 + O2→ H20 Al:O3 → Al + O2 8 5 Ch+ NaBr → NaCl + Bra 9 CuCla+ H2S → Zn + CuSO4 10 KCIO3 →KCI + 02 11 NAOH + HBr → H2O + Fe > 12 Assume you have ironl) in SMr products Ca(OH)2 + HNO3 → 13 Н.О + Fe > Synthesis Na:0 + CO2 → 14 Assume you have iron(l) in your products H2 + N2 →NH3 15
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