PRE-LABORATORY QUESTIONS1. 250.0 mL of a 2.500 M NaOH solution was mixed with 250.0 mL of a 2.500 M HCIltion in a calorimeter. Both the solutions were at the same temperature initially.Determine the heat of the reaction (kJ/mole), if the temperature goes from 2.0 °C to48.8 °C. The specific heat of the solution is 4.190 Jlg °C. Assume a density of 1.025g/mL.KETD2. 5.00 grams of calcium metal was reacted with 100.0 g of a 2.500 M HCI solution in acoffee cup calorimeter. The temperature went from 20.5 °C to 35.5 °C. Determine thereaction enthalpy per mole of calcium. The specific heat of the solution is 4.180 J/g oC.Assume a solution density of 1.03 g/mL.215

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Asked Oct 31, 2019
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Question 2

PRE-LABORATORY QUESTIONS
1. 250.0 mL of a 2.500 M NaOH solution was mixed with 250.0 mL of a 2.500 M HCI
ltion in a calorimeter. Both the solutions were at the same temperature initially.
Determine the heat of the reaction (kJ/mole), if the temperature goes from 2.0 °C to
48.8 °C. The specific heat of the solution is 4.190 Jlg °C. Assume a density of 1.025
g/mL.
KET
D
2. 5.00 grams of calcium metal was reacted with 100.0 g of a 2.500 M HCI solution in a
coffee cup calorimeter. The temperature went from 20.5 °C to 35.5 °C. Determine the
reaction enthalpy per mole of calcium. The specific heat of the solution is 4.180 J/g oC.
Assume a solution density of 1.03 g/mL.
215
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PRE-LABORATORY QUESTIONS 1. 250.0 mL of a 2.500 M NaOH solution was mixed with 250.0 mL of a 2.500 M HCI ltion in a calorimeter. Both the solutions were at the same temperature initially. Determine the heat of the reaction (kJ/mole), if the temperature goes from 2.0 °C to 48.8 °C. The specific heat of the solution is 4.190 Jlg °C. Assume a density of 1.025 g/mL. KET D 2. 5.00 grams of calcium metal was reacted with 100.0 g of a 2.500 M HCI solution in a coffee cup calorimeter. The temperature went from 20.5 °C to 35.5 °C. Determine the reaction enthalpy per mole of calcium. The specific heat of the solution is 4.180 J/g oC. Assume a solution density of 1.03 g/mL. 215

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Expert Answer

Step 1

The total mass of solution is calculated as,

Total mass mass of Ca mass of HCl
Total mass 5 100
Total mass 105 g
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Total mass mass of Ca mass of HCl Total mass 5 100 Total mass 105 g

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Step 2

The total heat can be calculated as,

Q mCAT
105 g x 4.180 J/g °C x (35.5 -20.5) °C
Q
Q 6583.5 J
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Q mCAT 105 g x 4.180 J/g °C x (35.5 -20.5) °C Q Q 6583.5 J

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Step 3

It is required to calculate the enthalpy per mole of calcium, hence calc...

Given mass
No. of moles
Molecular Mass
5
0.125 moles
No. of moles
40
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Given mass No. of moles Molecular Mass 5 0.125 moles No. of moles 40

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