Problem 2: A uniform rod of mass M = 2 kg and length L= 2 meters can pivot freely (i.e., ignore friction) about a hinge attached to a wall. The rod is held horizontally and then released from rest and allowed to swing downward. Assume the force of gravity acts at the center of mass of the rod, and that the moment of Inertia of the rod is I = 1/3 ML2. Find for the free end 1 1. The angular acceleration of the rod at the moment of release. 2. The angular speed when the rod is vertical. L/2 O = center of maśs

Problem 2: A uniform rod of mass M = 2 kg and length L= 2 meters can pivot freely (i.e., ignore friction) about a hinge attached to a wall. The rod is held horizontally and then released from rest and allowed to swing downward. Assume the force of gravity acts at the center of mass of the rod, and that the moment of Inertia of the rod is I = 1/3 ML2. Find for the free end 1 1. The angular acceleration of the rod at the moment of release. 2. The angular speed when the rod is vertical. L/2 O = center of maśs

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Static Equilibrium And Elasticity

Section: Chapter Questions

Problem 12.2OQ: A rod 7.0 in long is pivoted at a point 2.0 m from the left end. A downward force of 50 N acts at...

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