Problem 42 - IR spectrumProblem 42C13H9NO3MW = 22730-25-IR20-Hz, CDC13MRHz, CDC1315-10-Spec+EI350030002500200015001000Wavenumber (cm-1)emsof Contents Problem 42C13H9NO3Problem 42 - 1H NMR spectrum (CDC13, 500 MHz)MW = 2272H2HΗΝMR00 MHz, CDC132H2HC NMR25 MHz, CDC131HIass Spec0 eV +EIFroblemsTable of ContentsClick on the highlighted area to zoom Click again to zoom back out

Answered: Problem 42 C13H9NO3 Problem 42 - 'H NMR…

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Problem 42 C13H9NO3 Problem 42 - 'H NMR spectrum (CDC13, 500 MHz) MW = 227 2H =, CDC13 2H =, CDCI; 1H IE Contents

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

Problem 42 - IR spectrum
Problem 42
C13H9NO3
MW = 227
30-
25-
IR
20-
Hz, CDC13
MR
Hz, CDC13
15-
10-
Spec
+EI
3500
3000
2500
2000
1500
1000
Wavenumber (cm-1)
ems
of Contents

Problem 42
C13H9NO3
Problem 42 - 1H NMR spectrum (CDC13, 500 MHz)
MW = 227
2H
2H
ΗΝMR
00 MHz, CDC13
2H
2H
C NMR
25 MHz, CDC13
1H
Iass Spec
0 eV +EI
Froblems
Table of Contents
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Step 1:Introduction

NMR spectroscopy measures the effect of external magnetic field on the nuclei and helps in analysis of organic compounds while IR spectroscopy is the fingerprint of particular functional group.

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