Problem A moving electron has a Kinetic Energy Kg. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K4? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv², K2=(1/2)mv2 But it was mentioned that: v2=( so, Kz in terms of v, is K2=( )mv², Substituting the expression for K1 results to

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter6: Energy Of A System
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QUESTION 3
Problem
A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K4?
Solution
To solve for the work done, first we must determine what is the final kinetic energy of the electron.
By concept, we know that
K-(1/2)mv21
K2=(1/2)mv2
But it was mentioned that:
V2=(
so, K, in terms of v, is
K2=(
)mv2,
Substituting the expression for K, results to
K2=(
K1
Since work done is
W=AK=K
-K
Evaluating results to
W=(
)K1
Transcribed Image Text:QUESTION 3 Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K4? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K-(1/2)mv21 K2=(1/2)mv2 But it was mentioned that: V2=( so, K, in terms of v, is K2=( )mv2, Substituting the expression for K, results to K2=( K1 Since work done is W=AK=K -K Evaluating results to W=( )K1
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