Problem A moving electron has a Kinetic Energy Kg. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K-(1/2)mv², K2-(1/2)mv2 But it was mentioned that: so, K2 in terms of v, is K2=( )mv², Substituting the expression for K, results to K2=( )K1 Since work done is W-AK=K -K Evaluating results to )K1

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter6: Energy Of A System
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A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K4?
Solution
To solve for the work done, first we must determine what is the final kinetic energy of the electron.
By concept, we know that
K1=(1/2)mv²,
K2=(1/2)mv2
But it was mentioned that:
V2=(
so, K, in terms of v, is
K2=(
)mv²,
Substituting the expression for K, results to
K2=(
Since work done is
W=AK=K
Evaluating results to
W=(
)K1
Transcribed Image Text:Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K4? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv², K2=(1/2)mv2 But it was mentioned that: V2=( so, K, in terms of v, is K2=( )mv², Substituting the expression for K, results to K2=( Since work done is W=AK=K Evaluating results to W=( )K1
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