Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1-(1/2)mv²1 K2=(1/2)mv2 But it was mentioned that: v1 so, K2 in terms of v1 is K2=( mv², Substituting the expression for K1 results to K2= Since work done is W=AK=K Evaluating results to W=( )K1

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter6: Energy Of A System
Section: Chapter Questions
Problem 44P
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A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done Win terms of K1?
Solution
To solve for the work done, first we must determine what is the final kinetic energy of the electron.
By concept, we know that
K1=(1/2)mv²1
K2=(1/2)my2
But it was mentioned that:
v2=(
v1
so, K2 in terms of v1 is
K2=(
)mv²,
Substituting the expression for K1 results to
K2=(
Since work done is
W=AK=K
-K
Evaluating results to
W=(
K1
Transcribed Image Text:Problem A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done Win terms of K1? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv²1 K2=(1/2)my2 But it was mentioned that: v2=( v1 so, K2 in terms of v1 is K2=( )mv², Substituting the expression for K1 results to K2=( Since work done is W=AK=K -K Evaluating results to W=( K1
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