Problem Number 3: The block shown in the figure below is acted on by its weight, W = 650 KN, a horizontal force H = 450 KN., and the pressure P exerted by the inclined plane. The resultant R of these forces is parallel to the incline. Determine the Forces P and R. Does the block move up or down the incline? Y-axis W = 650 KN P = ? Х аxis H = 450 KN H=450 KN 35° 400 P= ? W=650 Forces X- Component Y- Component W = 650 KN Wx = -650sin 35 Wy = -650 cos 35 -372.824 -532.449 H = 450 KN Hx = 450 cos 35 Hy = - 450 sin 35 %3D %3D 368.618 - 258.109 P = ? Px = - P sin 5 Py = P cos 5 S Rx =R 0.000

Elements Of Electromagnetics
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2:04
Laz
ו 59% ב
Statics assignment 1.pub soln.pdf
Problem Number 3:
The block shown in the figure below is acted on by its weight, W = 650 KN, a horizontal
force H = 450 KN., and the pressure P exerted by the inclined plane. The resultant R of
these forces is parallel to the incline. Determine the Forces P and R. Does the block
move up or down the incline?
Y-axis
W = 650 KN
P = ?
X axis
H = 450 KN
H=450 KN
35°
40°
P= ?
W=650
Forces
X- Component
Y- Component
W = 650 KN
Wx = -650sin 35
Wy = -650 cos 35
-372.824
-532.449
H = 450 KN
Hx = 450 cos 35
Hy = - 450 sin 35
368.618
- 258.109
P = ?
Px = - P sin 5
Py = P cos 5
S
Rx =R
0.000
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Transcribed Image Text:2:04 Laz ו 59% ב Statics assignment 1.pub soln.pdf Problem Number 3: The block shown in the figure below is acted on by its weight, W = 650 KN, a horizontal force H = 450 KN., and the pressure P exerted by the inclined plane. The resultant R of these forces is parallel to the incline. Determine the Forces P and R. Does the block move up or down the incline? Y-axis W = 650 KN P = ? X axis H = 450 KN H=450 KN 35° 40° P= ? W=650 Forces X- Component Y- Component W = 650 KN Wx = -650sin 35 Wy = -650 cos 35 -372.824 -532.449 H = 450 KN Hx = 450 cos 35 Hy = - 450 sin 35 368.618 - 258.109 P = ? Px = - P sin 5 Py = P cos 5 S Rx =R 0.000 PREVIOUS 3/3 NEXT II
2:04
ו 59%ב
Laz
Statics assignment 1.pub soln.pdf
Problem Number 2:
The Force system shown has a resultant of 320 lbs pointing down along the Y-
axis. Compute the values of F and e required to give the resultant.
S=420 Lbs
Sy
420 Ibs
Sx
Sx
Sx
e = ?
T= 900 Lbs
25°
F = ?
R=320 Ibs
Forces
X- Component
Y- Component
T = 900 Lbs
Tx = 900
Ty = 0
S = 420 Lbs
Sx = - 420 cos e
Sy = 420 sin e
F = ?
Fx = -F cos 25
Fy = - Fsin 25
S
0.00
-320 Ibs
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Transcribed Image Text:2:04 ו 59%ב Laz Statics assignment 1.pub soln.pdf Problem Number 2: The Force system shown has a resultant of 320 lbs pointing down along the Y- axis. Compute the values of F and e required to give the resultant. S=420 Lbs Sy 420 Ibs Sx Sx Sx e = ? T= 900 Lbs 25° F = ? R=320 Ibs Forces X- Component Y- Component T = 900 Lbs Tx = 900 Ty = 0 S = 420 Lbs Sx = - 420 cos e Sy = 420 sin e F = ? Fx = -F cos 25 Fy = - Fsin 25 S 0.00 -320 Ibs PREVIOUS 2/3 NEXT II
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