Professional photographers most commonly use digital photography now. However, some photographers still prefer the quality of the image and the developing process of black and white film compared to digital images. A photographic stop bath is a chemical bath used in processing black and white film. When developing black and white film, a basic developing solution is used to have the pictures develop from the film. The stop bath solution is a dilute 1 to 2% acetic acid solution, and it is applied to the film to stop immediately the development of the film. If the electrical conductivity of the stop bath solution was tested, what degree of electrical conductivity would be expected? Explain MAMUT

Professional photographers most commonly use digital photography now. However, some photographers still prefer the quality of the image and the developing process of black and white film compared to digital images. A photographic stop bath is a chemical bath used in processing black and white film. When developing black and white film, a basic developing solution is used to have the pictures develop from the film. The stop bath solution is a dilute 1 to 2% acetic acid solution, and it is applied to the film to stop immediately the development of the film. If the electrical conductivity of the stop bath solution was tested, what degree of electrical conductivity would be expected? Explain MAMUT

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter16: Solutions

Section: Chapter Questions

Problem 100E: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a...

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Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a primary standard. It has the formula KHC8H4O4. This is often written in the short-hand notation as KHP. If 25.0mL of a potassium hydroxide solution are needed to neutralize 2.26g of KHP, what is the molarity of the potassium hydroxide solution? Potassium hydrogen phthalate sometimes called potassium biphthalate, as shown on this bottle is an acid that is convenient to store and use because it is a solid.
The total cation content of natural water is often determined by exchanging the cations for hydrogen ions on a strong acid ion-exchange resin. A 25.00 mL sample of a natural water was diluted to 100.00 ML with distilled water, and 2.06 g of a cation - exchange resin was added. After stirring, the mixture was filtered and the solid remaining on the filter paper was washed with three 15.00 mL portions of water. The filtrate and washings required 16.30 mL of 0.0282 M NaOH to give a bromocresol green end point. a) Calculate the number of millimoles of cation present in exactly 1.00 L of sample. b ) Report the results in terms of milligrams of CaCO3 per liter. Only typed solution.
Make an schematic diagram for procedure below: B. %SO3 determination Transfer all precipitate to the filter paper avoiding any loses during the filtration procedure. One may use a rubber policeman to scrape remaining precipitate in the beaker. Wash the precipitate in the beaker 3x with hot water before transferring to the filter paper. Test the washings with 0.1 M AgNO3 Cloudiness indicates presence of chloride ions; therefore there is a need to wash more the precipitate. Carefully lift the paper out of the funnel, fold it as demonstrated by your instructor and transfer it onto the constant weighed crucible. Dry the crucible cautiously with a small flam, as instructed by your instructor. The flame should be directed at the top of the container, and the lid should be off. Avoid spattering. After drying, char the filter paper by increasing the flame temperature. The crucible should have free access to air. The lid should be kept handy to smother the filter paper in case it catches fire.…
A student was tasked to perform gravimetric analysis of a soluble sulfate. His unknown sample weighed 0.7543 g. The sample underwentprecipitation using BaCl2 and was digested for overnight. The precipitate was then filtered off to obtain white crystalline precipitate that was collected inan ash less filter paper. In performing constant weighing, he obtained a crucible mass that is 29.9442 g. After burning his samples inside the crucible,the obtained mass was 30.3375 g. Compute for the theoretical % SO3 obtained by the student and the theoretical mass (g) of SO3 that should be obtained by the student using his weighed sample
A student was tasked to perform gravimetric analysis of a soluble sulfate. His unknown sample weighed 0.7543 g. The sample underwentprecipitation using BaCl2 and was digested for overnight. The precipitate was then filtered off to obtain white crystalline precipitate that was collected inan ash less filter paper. In performing constant weighing, he obtained a crucible mass that is 29.9442 g. After burning his samples inside the crucible,the obtained mass was 30.3375 g.29. Compute for the mass (g) of BaSO4 from the experiment.A) 0.3933B) 0.3393C) 0.3133D) 0.3951E) 0.359130. Compute for the experimental mass (g) of SO3 in grams obtained by the student.A) 0.1439B) 0.1349C) 0.1943D) 0.1394E) 0.359131. Compute for the experimental % SO3 obtained by the student.A) 73.21B) 56.33C) 17.89D) 56.89E) 72.8032. Compute for the theoretical % SO3 obtained by the studentA) 0.3933B) 56.37C) 17.33D) 17.89E) 0.425233. Compute for the theoretical mass (g) of SO3 that should be obtained by the student…
A stock salt solution is prepared by dissolving 5.69 g of table salt in water and diluting the mixture to 150 mL with water. A 15 mL of the stock salt solution is then taken and diluted to 150 mL with water. The concentration of second solution is ___ the strength of the stock salt solution.
PS. Further values required for the solvings are give in the various situations below. (ANSWER) Situation: A community in a mountainous area of Bohol uses water collected from a nearby natural spring. A sample was submitted to a laboratory for the analysis of its total hardness. Required: SHOW YOUR COMPLETE CALCULATIONS. BASED ON THE IMAGE PROVIDED BELOW FOR THIS QUESTION: Calculate the amount of titrant used in each trial to reach endpoint. Report total hardness of the sample as mean ±sd. a. 250.0 mL of 500.0 ppm of CaCO3 solution from a primary standard (assume solvent is distilled water only). Answer : Mass of CaCO3 = 0.125 g b, The EDTA solution was standardized by titrating it with a 25.0 mL aliquot of the CaCO3 solution. How much of the titrant was consumed. Answer: Volume of EDTA consumed = 12.405 g c. Calculate the average titer (mg CaCO3/mL EDTA). Mass of CaCO3 in 25 mL CaCO3 solution: 0.0125 g Answer: 1.008 mg CaCO3/ mL EDTA
Can you please please please not reject this question. I really need to know this. AND THIS IS NOT A GRADED QUESTION. So can someone please answer this without rejecting this everytime. I really need to learn how to do the calculations for this becuse I have my exam within 2 weeks. So please someone and this is not a graded question. Okay this time I have included all the information. Molarity is included. An experiment was conducted by following the procedure below. Prepare a 50-mL burette for titration. Rinse the clean burette and tip with two 5-mL portions of standardized 0.005 M HCl solution and discard. Fill the burette with standardized HCl, remove the air bubbles in the tip, and record the initial volume (± 0.01mL). Record the molarity of the HCl solution, which is 0.005M Cover the flask with parafilm to avoid contact with carbondioxide from air. Rinse a 25 mL pipet with 1 or 2 mL of the saturated Ca(OH)2 solution and discard. Pipet 25 mL of the filtrate into a clean…
00 mL of a diprotic acid primary standard solution was accurately prepared to a concentration of 0.1431 M. Three samples of this primary standard solution were used as samples in a titration to standardize an aqueous solution of sodium hydroxide, NaOH, which would be used as a titrant. Using the following table of data for the titration of the primary standard acid with NaOH, calculate the average concentration of NaOH. Trial # Volume of primary standard Initial titrant volume Final titrant volume 1 10.00 mL 8.21 mL 27.22 mL 2 10.00 mL 27.22 mL 46.23 mL 3 10.00 mL 30.28 mL 49.29 mL 0.1506 M 0.0753 M 0.0376 M 0.1431 M 0.0526 M
A local company sent you their green alternative for window cleaner to be tested for percent (w/v) acetic acid content. For your experiment, you first standardized your NaOH titrant with 0.8053 g of (99.80 % purity) KHP. You used 40.60 mL of NaOH for your standardization. After that you then analyzed a 10.00 mL sample and found that you needed 43.20 mL NaOH to reach the end point. Summary of results: Standardization Sample analysis KHP Weight (g) 0.8053 g Volume of sample 50.00 mL Purity 99.80% NaOH (mL) used 33.20 mL NaOH (mL) used 40.60 mL Determine the following: Molarity of NaOH % (w/v) acetic acid
As a food chemist for a major potato chip company, you are responsible for determining the salt content of new potato chip products for the packaging label. The potato chips are seasoned with table salt, NaCl. You weigh out a handful of the chips (78.5 g), boil them in water to extract the salt, and then filter the boiled chips to remove the soggy chip pieces. You then analyze 100.0 mL of the chip filtrate for Cl- concentration using the Mohr method. First, you prepare a solution of AgNO3, and standardize it using 0.500 g KCl as the primary standard. Calculate for the concentration (in M) of the standard AgNO3 solution if it takes 64.5 mL of the AgNO3 titrant to reach the equivalence point of the reaction. Write the balance chemical reaction between the standard and the titrant. You then use the standardized AgNO3 solution to analyze the chip filtrate in a Mohr reaction, finding that the solution yields a rusty brown precipitate when 48.8 mL of titrant is added. Calculate for the…
Identify different industries and commercial products where the gravimetric analysis can be used and discuss the significance of gravimetric analysis in the above identified industry/commercial products (minimum three).