Protein phosphatase 1 (PP1) helps regulate cell division and is a possible drug target to treat certain types of cancer. The enzyme catalyzes the hydrolysis of a phosphate group from myelin basic protein (MBP). The activity ofPP1 was measured in the presence and absence of the inhibitor phosphatidic acid (PA).[MBP](mg-mL-¹)0.0100.0150.0250.050Vo without PA(nmol-mL-¹ min-¹)0.02090.03550.04190.0838Use the data in the table to construct a Lineweaver-Burk plot. What type of inhibitor is phosphatidic acid?UncompetitiveNoncompetitiveMixed inhibitionCompetitiveVo with PA(nmol-mL-¹ min-¹)0.003810.006200.009310.01400

Answered: Image /qna-images/answer/e8f06948-b6da-4005-8642-e92a01cad44c.jpg

Protein phosphatase 1 (PP1) helps regulate cell division and is a possible drug target to treat certain types of cancer. The enzyme catalyzes the hydrolysis of a phosphate group from myelin basic protein (MBP). The activity of PP1 was measured in the presence and absence of the inhibitor phosphatidic acid (PA). [MBP] (mg-mL-1) 0.010 0.015 0.025 0.050 Vo without PA (nmol-mL-¹ min-¹) Uncompetitive Noncompetitive Mixed inhibition Competitive 0.0209 0.0355 0.0419 0.0838 Vo with PA (nmol-ml-1.min-¹) 0.00381 Use the data in the table to construct a Lineweaver-Burk plot. What type of inhibitor is phosphatidic acid? 0.00620 0.00931 0.01400

Protein phosphatase 1 (PP1) helps regulate cell division and is a possible drug target to treat certain types of cancer. The enzyme catalyzes the hydrolysis of a phosphate group from myelin basic protein (MBP). The activity of PP1 was measured in the presence and absence of the inhibitor phosphatidic acid (PA). [MBP] (mg-mL-1) 0.010 0.015 0.025 0.050 Vo without PA (nmol-mL-¹ min-¹) Uncompetitive Noncompetitive Mixed inhibition Competitive 0.0209 0.0355 0.0419 0.0838 Vo with PA (nmol-ml-1.min-¹) 0.00381 Use the data in the table to construct a Lineweaver-Burk plot. What type of inhibitor is phosphatidic acid? 0.00620 0.00931 0.01400

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter18: Chemical Kinetics

Section: Chapter Questions

Problem 75AP

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A substance undergoes first-order decomposition. After 40.0 min at 500°C, only 12.5% of the original sample remains. YYliat is the half-life of the decomposition? If the original sample weighed 243 g, how much would remain after 2.00 h?
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The oxidation of iodide ion by the hypochlorite ion in the presence of hydroxide ions I(aq) + ClO(aq) IO(aq) + Cl(aq) was studied at 25 C, and the following initial rates data (Y. Chia and R. E. Connick, Journal of Physical Chemistry, Vol. 63, p. 1518, 1959) were collected: (a) Determine the rate law for this reaction. (b) One mechanism that has been proposed for this reaction is the following: Show that the rate law predicted by this mechanism matches the experimentally determined rate law in part a. (Note that when writing the expression for K the equilibrium constant, [H2O] is not involved. See Chapter 15.)
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Consider the following reaction: CH3X+YCH3Y+X At 25C, the following two experiments were run, yielding the following data: Experiment 1: [Y]0 = 3.0 M [CH3X] (mol/L) Time(h) 7.08 103 1.0 4.52 103 1.5 2.23 103 2.3 4.76 104 4.0 8.44 l05 5.7 2.75 l05 7.0 Experiment 2: [Y]0 = 4.5 M [CH3X] (mol/L) Time(h) 4.50 103 0 1.70 103 1.0 4.19 104 2.5 1.11 104 4.0 2.81 l05 5.5 Experiments also were run at 85C. The value of the rate constant at 85C was found to be 7.88 108 (with the time in units of hours), where [CH3X]0 = 1.0 102 M and [Y]0 = 3.0 M. a. Determine the rate law and the value of k for this reaction at 25C. b. Determine the half-life at 85C. c. Determine Ea for the reaction. d. Given that the C8X bond energy is known to be about 325 kJ/mol, suggest a mechanism that explains the results in parts a and c.
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