Q2- A 30.0 ml H2C¿O4 acidified solution, was treated with 25.0 ml of 0.102 M KMNO4 solution. The reaction: 2MNO4- + 5 H2C204+ 6H → 2MN2* +10CO2 + 8H20 The excess permanganate required 8.34 ml of 0.053 M Fe2* solution, the reaction Mn04 + 5FE2* + 8H+ g Mn2+ +5FE3+ + 4H20 Find the molarity of the H2C2O4 solution
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Q: Q2- A 30.0 mL H2C2O4 acidified solution, was treated with 25.0 mL of 0.102 M KMNO4 solution. The…
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Q: Q2- A 30.0 mL H2C2O4 acidified solution, was treated with 25.0 mL of 0.102 M KMNO4 solution. The…
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Q: Q2- A 30.0 ml H2C2O4 acidified solution, was treated with 25.0 ml of 0.102 M KMNO4 solution. The…
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- Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW =60.05) was added to a 1 –liter volumetric flask, and the flask was filled to the mark with distilled water. A portion of the resulting solution was added to a conductance cell (k = 1.25 cm-1), and the conductance was found to be 416 μS. Calculate the dissociation constant Ka of acetic acid. ΛoH+= 349.8 Scm2/mole and ΛoCH3COO- = 41 Scm2/moleH2S(aq) is analyzed by titration with coulometrically generated I2 in Reactions 17-3a and 17-3b. To 50.00 mL of unknown H2S sample were added 4 g of KI. Electrolysis required 812 s at 52.6 mA. Find the concentration of H2S (mg/mL)in the sample.Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (FM 214.00) in a 500-mL volumetric flask. Then 50.00 mL of the solution were pipetted into a flask and treated with excess KI (2 g) and acid (10 mL of 0.5 M H2SO4) to drive Reaction 16-20 to completion. How many moles of I23 are created by the reaction?
- The ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL portion of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH:CH3COOC2H5 + OH- → CH3COO- + C2H5OHAfter cooling, the excess OH2 was back-titrated with 3.41 mL of 0.05042 M H2SO4. Calculate theamount of ethyl acetate (88.11 g/mol) in the original sample in gramsDESCRIBE THE PROCEDURE OF d) 600 mL of 3.00% (w/v) aqueous BaCl2from a 0.400 M BaCl2solution. (e) 2.00 L of 0.120 M HClO4from the commercial reagent [71.0% HClO4(w/w), specificgravity1.67]. (f) 9.00 L of a solution that is 60.0 ppm in Na+, starting with solid Na2SO4Using the term u of KSP experimental procedure the 6 p.m. As you add 5 ml of .004M AgNo to 5ml of .0025M K2CrO4. Is either of these reagents in excess? If so which one?
- Six iron tablets containing FeSO4.7H2O were dissolved in 100-ml of 0.1M HNO3 with gentle heating. All of the Fe2+ is converted to Fe3+ by the strong oxidizing conditions. After the solution had cooled to room temperature , 2.5-ml of 35wt% NH4OH was added. The precipitate Fe2O3-xH2O that was filtered weighed 0.345g. Thermogravimetric analysis of the crude product showed a 10.5% weight loss . A. How many waters of hydration were in the precipitate B. How much iron is present in each tabletFollowing the monograph procedure, a 724-mg of aspirin (MW=180 g/mol) dissolved in 18.5 ml of cold neutralized alcohol. This solution was then initially titrated with 0.101 N sodium hydroxide solution, then later neutralized with 0.104 sulfuric acid. What is the percentage purity of the sample? 1. What is the milliequivalent weight consumed by the acidic titrant? a. 1.5392 g-meq b. 2.0907 g-meq c. 1.4948 g-meq d. 2.1528 g-meq 2. What is the milliequivalent weight consumed by the basic titrant? a. 5.8656 g-meq b. 1.5392 g-meq c. 5.6964 g-meq d. 1.4948 g-meq 3. What is the difference of milliequivalent weight consumed in the reaction? a. -4.1572 g-meq b. 4.3708 g-meq c. 0.5515 g-meq d. 4.1572 g-meqThe Tl in a 9.76-g sample of rodenticide was oxidized to the trivalent state and treated with an unmeasured excess of Mg/EDTA solution. The reaction is Tl+3 + MgY-2 → TlY- + Mg+2 . Molecular mass: Tl2SO4 = 504.8 a. Titration of the liberated Mg2+ required 13.34-mL of 0.03560 N EDTA. The type of titration involved in the assay is (direct/indirect/residual) ______? b. percentage of Tl2SO4 in the sample is __________ %?
- Find the conc of free Mg2+ in 0.050 M Na2[Mg(EDTA)](i.e. MgY2-) at pH 9.00.A 20 ml aliquot of malonic acid solution was treated with 10.0 ml of 0.25M Ce4+ leading to the reaction CH2(COOH)2 + 6Ce4+ + 2H2O ® HCOOH + 2CO2 + 6Ce3+ + 6H+ After standing for 10 minutes at 60oC, the solution was cooled and the x’ss Ce4+ was titrated with 0.1M Fe2+, requiring 14.4 ml to reach the ferroin end point. Calculate the M of the malonic in the sample.A 50 mL sample solution containing 8-hydroxyquinoline (MW: 145) was analyzed by adding 25 ml, 0.1 M KBrO3, excess KBr and acidified. The mixture was left for 10 minutes in dark place. After this time KI in excess was added followed by titration with 27.9 mL, 0.05 M thiosulfate standard solution. Write balance equations? What is the percent w/v 8-hydroxyquinoline in sample?