A 25.00-mL sample of La31 was treated with excess Na2C2O4 to precipitate La2(C2O4)3, which was washed to remove excess C2O4 22 and then dissolved in acid. The oxalate from La2(C2O4)3 required 12.34 mL of 0.004 321 M KMnO4 to reach the purple end point of Reaction 6-1. Find the molarity of La31 in the unknown.
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A 25.00-mL sample of La31 was treated with excess Na2C2O4 to precipitate La2(C2O4)3, which was washed to remove excess C2O4 22 and then dissolved in acid. The oxalate from La2(C2O4)3 required 12.34 mL of 0.004 321 M KMnO4 to reach the purple end point of Reaction 6-1. Find the molarity of La31 in the unknown.
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- 1.) A 0.1278-g sample of primary standard Na2C2O4 required exactly 60.04 mL of permanganate solution to reach the end point. What is the molarity of the KMnO4 reagent? 2.) A 50.00 mL sample containing La3+ was added with sodium oxalate to precipitate La2(C2O4)3, which was washed, dissolved in dilute H2SO4, and titrated with 18.09 mL of the standard KMnO4 solution (in #1). Calculate the molarity of La3+ in the unknown sample.A 500.0mg of butter was warmed and shaken vigorously with water. The undissolved material was removed by filtering and the aqueous portion was made 1.0M in HNO3 and 0.025M in Fe(NO3)3. This acidified solution was treated with 10.00ml of 0.1755M AgNO3 to precipitate the chloride ion and, after the addition of a small amount of nitrobenzene, 14.22ml of 0.1006M KSCN was required to back titrated the excess Ag+. Calculate the % NaCl in the butter.A student found that 0.076 g of PbF2 was dissolved in 220 . mL of saturated PbF2. What is the Ksp for the lead(II) fluoride? (Enter your answer as follows: 1.0e-2 for 0.010). Ksp =
- A 25 ml solution of unkown containing Fe+3 and Ca+2 required 16.06 ml of 0.051 M EDTA for complete the reaction. A 50 ml of the same of the unkown was treated with NH4F to protect Fe+3. then the Ca+2 was reduced and masked by addition thiourea. upon addition of 25 ml of 0.051 M EDTA, the Fe+3 was liberated fron its floride complex and formed EDTA complex . the excess ETDA required 19.77 ml of 0.01883 M pb+2 to reach the end point by using xylenol orange indicator. Find the concentarion of Ca+2 in the unkown sample?The Tl in a 9.76-g sample of rodenticide was oxidized to the trivalent state and treated with an unmeasured excess of Mg/EDTA solution. The reaction is Tl+3 + MgY-2 → TlY- + Mg+2 Titration of the liberated Mg2+ required 15.34-mL of 0.08560 N EDTA. The type of titration involved in the assay is ___ (direct/indirect/residual) and the percentage of Tl2SO4 in the sample is ____%. Molecular mass: Tl2SO4 = 504.8A 25.00 mL sample containing Fe3+ was treated with 10.00 mL of 0.03676 M EDTA to complex all the Fe3+ and leave excess EDTA in solution. The excess EDTA was then back-titrated, requiring 2.37 mL of 0.04615 M Mg2+. What was the concentration of Fe3+ in the original solution in ppm Fe3+?
- A 25.00-mL sample containing Fe3+ was treated with 10.00 mL of 0.036 7 M EDTA to complex all the Fe3+ and leave excess EDTA in solution. The excess EDTA was then back titrated, requiring 2.37 mL of 0.0461 M Mg2+. What was the concentration of Fe3+ in the original solution?Which of the following experiments can be described as a displacement titration? A. Calcium in powdered milk is determined by dry ashing a 1.50 g sample and then titrating the calcium with 12.1 mL of 0.008949 M EDTA. B. The Tl in a 9.57-g sample of rodenticide was oxidized to the trivalent state and treated with an unmeasured excess of Mg/EDTA solution. The reaction is Tl3+ + MgY2- -> TlY- + Mg2+ Titration of the liberated Mg2+ required 12.77 mL of 0.03610 M EDTA. C. A 3.650-g sample containing bromide was dissolved in sufficient water to give 250.0 mL. After acidification, silver nitrate was introduced to a 25.00-mL aliquot to precipitate AgBr, which was filtered, washed, and then redissolved in an ammoniacal solution of potassium tetracyanonickelate(II): Ni(CN)42- + 2AgBr(s) -> 2Ag(CN)2- + Ni2+ + 2Br- The liberated nickel ion required 26.73 mL of 0.02089 M EDTA. D. A solution contains 1.569 mg of CoSO4 (155.0 g/ mol) per milliliter. 50.00 mL of 0.007840 M EDTA…A 1.000-g sample containing bromide was dissolved in sufficient water to give 100.0 mL. A 50.00 mL aliquot was measured and after acidification, silver nitrate was introduced to precipitate AgBr, which was filtered, washed, and then dissolved in an ammoniacal solution of potassium tetracyanonickelate(II): Ni(CN)42- + 2AgBr(s) → 2Ag(CN)2- + Ni2+ + 2Br- The liberated nickel ion required 11.70 mL of 0.002146 M EDTA. Calculate mmol Ni in the 50.00 mL aliquot. Calculate mmol Br- in the 50.00 mL aliquot. Calculate the percentage of NaBr (102.894) in the 1.000 g sample.
- A 1.000-g sample containing bromide was dissolved in sufficient water to give 100.0 mL. A 50.00 mL aliquot was measured and after acidification, silver nitrate was introduced to precipitate AgBr, which was filtered, washed, and then dissolved in an ammoniacal solution of potassium tetracyanonickelate(II): Ni(CN)42- + 2AgBr(s) → 2Ag(CN)2- + Ni2+ + 2Br- The liberated nickel ion required 11.70 mL of 0.002146 M EDTA The other 50.00 mL remaining solution was also analyzed for its Br- content by potentiometry using a metallic electrode of the second kind. Ecell recorded in running the solution using the potentiometric set-up was Ecell = 0.0286 V. (E0Ag/AgBr = 0.095 V) g) Compute for Eind. h) Compute pBr in the 50.00 mL aliquot. i) Compute for % NaBr ( in the potentiometric technique). j) Calculate the error between the obtained % NaBr fr the EDTA titration technique and the % NaBr from the potentiometric technique.The Tl in a 9.76-g sample of rodenticide was oxidized to the trivalent state and treated with an unmeasured excess of Mg/EDTA solution. The reaction is Tl+3 + MgY-2 → TlY- + Mg+2 . Molecular mass: Tl2SO4 = 504.8 a. Titration of the liberated Mg2+ required 13.34-mL of 0.03560 N EDTA. The type of titration involved in the assay is (direct/indirect/residual) ______? b. percentage of Tl2SO4 in the sample is __________ %?A carbonate fusion was needed to free the Bi from a 0.6400-g sample containing the mineral eulytite (2Bi2O3. 3SiO2). The fused mass was dissolved in 25.00 mL dilute acid, following which the Bi3+was titrated with 27.00mL of 0.03400M NaH2P04. The reaction is Bi3++ H2PO4-BiPO4(s) + 2H+ Identify: (a) possible chemical indicator for this analysis (b) Calculate the weight percent purity of eulytite (FW=1112.17g/mol) in the sample.