A foot powder sample containing Zn was dissolved on 50.00 ml water and was titrated to the end point color with 22.57 ml of 0,01639 M EDTA at pH=D4. (a4= 3.61×10 , KZnY2 = 3.2 x 10). The pZn in the sample is
Q: If 200 ml of 0.01 M EDTA is added to 100 ml of 0.01 M Ni solution that is buffered at PH of 10.2,…
A:
Q: foot powder sample containing Zn was dissolved on 200.0 mL water and was titrated to the end point…
A:
Q: 2.054 g of macrogol monostearate (average molecular weight 706. 5) was added to a 200 ml flask and…
A: Solution: We know the saponification reaction i.e the base catalysed hydrolysis reaction of an ester…
Q: A 50.00-mL aliquot of solution containing 0.358 of MgSO4 (FM 120.37) in 0.500 L required 38.08 mL of…
A: Solution - According to the question - Given - Total Moles of Mg2+ = moles of MgSO4 = mass/molar…
Q: For the titration of 50.00 mL of 0.000226 M Ba²* with 0.100 M EDTA at pH 10.00, ay = 0.30, and Kf =…
A:
Q: Pt (II) and TI (III) are two metals that can be determined by UV spectrophotometry with…
A: Given: The molar absorptivity coefficient for Tl (III) at a max of 621 nm is 5.64×104 M-1 cm-1. The…
Q: The Cr plating on a surface that measured 3.00 cm x 4.00 cm was dissolved in HCl. The pH was…
A: Given : molarity of EDTA : 0.01441M Volume of EDTA = 10.19mL Total amount of EDTA or milimole of…
Q: The Cr plating on a surface that measured 3.00 cm x 4.00 cm was dissolved in HCI. The pH was…
A:
Q: A 2.00 mL sample of commercial bleach was diluted with water to a 100.00 mL volumetric flask. A…
A: The ratio of mass of solute in 100 mL of solution is known as %w/v
Q: A carbonate fusion was needed to free the Bi from a 0.6400-g sample containing the mineral eulytite…
A: Given, Bi3+ + H2PO4- →BiPO4(s) + 2H+ mass of eulytite sample = 0.64 g molarity of NaH2PO4 = 0.0340 M…
Q: A total of 5 mL of blood samples were treated with trichloroacetic acid to precipitate proteins.…
A: Solution: In this problem we have to calculate the concentration of Pb in ppm
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: This classical method of determination of Hardness of water by titration of Standard and unknown…
Q: 50.0-mL sample containing Ni2+ was treated with 25.0 mL of 0.0500 M EDTA to complex all the Ni2+ and…
A:
Q: What is the concentration of SCN" in a solution prepared by adding 5.0 mL of 0.0020M SCN" to a test…
A:
Q: A 60.00 mL of buffered solution (pH 10) containing Zn2* and Ni2* ions (from a chip sample) is…
A: Metal ion combine with EDTA in 1 : 1 mole ratio. So we would calculate moles of both metal ions…
Q: A 50.00 mL sample of water was collected from a faucet. A 10.00 mL aliquot of this sample was placed…
A: EDTA and Ca+2 forms 1:1 complex Number of moles of standard EDTA consumed = molarity * volume =…
Q: Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW=60.05) was added to a 1-liter volumetric…
A: 6.00 mL of acetic acid was added to a 1 L flask and filled with distilled water . A conductance…
Q: Determine the conditional formation constant (K") for a solution containing 7.50 × 10-3 M Cay2-,…
A: The condition formation constant (K"f) for the solution is calculated as shown below.…
Q: A batch of codeine phosphate powder was analysed according to the BP (1999) method described below.…
A: The amount of codeine phosphate, C18H21NO3.H3PO4(s) is quantitatively determined by non-aqueous…
Q: Given the approximate Kf values: Ca-EDTA = 1010 ; Mg-EDTA = 10 ; Fe-EDTA = 1014 ; Hg-EDTA = 1021;…
A: Correct answer (B)
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: Given data; Mass of solid CaCO3 is 3.1251 g The volume of dilute HCl for prepare CaCO3 solution is…
Q: A 100, 0mL containing Zn^ 2+ was treated with 50.0 of 0.0500 M EDTA complex all the Zn^ 2+ and leave…
A: We have given that 100mL containing Zn2+ was treated with 50.0ml of 0.0500 M EDTA complex excess…
Q: Solution made by mixing 5mL of 0.030M Co2(SO4)3 with 40mL of 0.0120M EDTA was adjusted to pH 10.…
A: Given: Concentration of Co2(SO4)3 = 0.030 M Volume of Co2(SO4)3 = 5 mL Concentration of EDTA =…
Q: For the titration of 20.0 mL of 0.0100 M EDTA with 50.0 mL of 0.0200 M MNPO4 at pH = 10.00,…
A: The given information is: Volume of EDTA = 20.0ml Molarity of EDTA= 0.010 M Volume of MnPO4 = 50.0ml…
Q: Calculate the pZn2+ for solutions prepared by adding 0.00, 5.00, 10.00, 15.00, 20.00, 25.00 and…
A: The concentration of Zn2+ can be determined as: M1V1(Zn2+)=M2V2(EDTA) pZn2+ can be determined by:…
Q: A volume of 50.00 ml of 0.01800 mol L-1 EDTA solution was added to a solution containing 0.02550 g…
A:
Q: A 25 ml solution of unkown containing Fe+3 and Ca+2 required 16.06 ml of 0.051 M EDTA for complete…
A: Back titration is a process where the unknown concentration of an analyte is determined by reacting…
Q: A 50.0 mL aliquot of solution contairing 0.450 g of MgSO4 (FM 120.37) in 0.500L required 37.6 mL of…
A: EDTA titration :- It is a complexometric titrations . EDTA is short form of…
Q: 1. How much volume (mL) is needed to standardize 0.05M of EDTA using 180mg of magnesium ribbon? MW:…
A:
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: Given data contains, Mass of solid CaCO3 is 3.1251g. Volume of dilute hydrochloric acid for…
Q: A cyanide solution with a volume of 12.99 ml was treated with 30.00 mL. of Ni solution (containing…
A:
Q: A 1.509-g samle of a Pb/Cd alloy was dissolved in acid and diluted to exactly 250.0 mL in a…
A: The explanation is given below-
Q: You are asked to titrate a Mn3+ solution with EDTA at pH 9.00. The overall ionic strength of the…
A: Given- Log k = 25.2k =1025.2now αEDTA4-=5.4 ×10-2×1025.2 (a).k'(conditional formation constant…
Q: A cyanide solution with a volume of 13.87 mL was treated with 24.00 mL of Ni+ solution (containing…
A: Concentration of CN- can be determined from the amount of Ni2+ used in the titration of CN-.
Q: Calculate the pZn2+ for solutions prepared by adding 0.00, 5.00, 10.00, 15.00, 20.00, 25.00 and…
A: Note - Since you have posted a question with multiple sub-parts, we will solve first three…
Q: Triplicate samples of NaOH was found to have concentrations of 0.1444 M (Trial 1), 0.1107 M (Trial…
A: Introduction : Titration can be defined as the technique where a solution of known concentration is…
Q: A sample of toothpaste was analyzed for its fluoride content by treating a 250 mg sample with an…
A:
Q: A 25.00-mL sample containing Fe3+ was treated with 10.00 mL of 0.036 7 M EDTA to complex all the…
A: In the question Following information given - Volume of Fe3+ Solution = 25 mL Volume of EDTA = 10 mL…
Q: A water sample was tested for water hardness. A 50.00 mL sample, prepared and buffered to pH 10,…
A: Calculate number of moles of EDTA: 1 mL = 0.001 L No.of moles=Molarity×Volume…
Q: In a solution kept constant by buffering to pH= 8.0, 50.0 mL of 0.0050 M Ni2+ is 0,0100 İn titration…
A: The question is based on the concept of quantitative analysis. We have to calculate pNi at different…
Q: chip sample) is analyzed using EDTA titration with EBT as indicator. The following data were…
A:
Q: The stability contact values of M1-EDTA, M2-EDTA, M3-EDTA, M-EDTA complexes are 2.1 x 10", 7.8 x…
A: In EDTA Titration,larger stability constant indicates that the reaction is more complete and larger…
Q: aliquot was then titrated with EDTA 0.0040 mol/L and the average volume spent was 15.01 mL. To…
A: Given: Mass of tablet=1.25g Volume of solution=1.0L Volume of aliquot = 10.0mL Molarity of…
Q: 50 mL of a solution of 0.0200 M Zn2+ will be titrated with 0.0100 M EDTA in 0.0100 M NH3 at pH…
A: given values = K1 = 1.02 x 10-2, K2= 2.14 x 10-3, K3 = 6.92 x 10-7 and K4 = 5.50 x 10-11. pH = 6.0
Q: You are asked to titrate a Mn3+ solution with EDTA at pH 9.00. The overall ionic strength of the…
A: Solution- Log k = 25.2k =1025.2 nowαEDTA4−=5.4 ×10−2×1025.2 at pH=9(a) k'(conditional formation…
Q: To a 50.00-mL aqueous solution containing Pb2+ is added a total amount of 5.000 mmol EDTA. The pH…
A: This is a method of quantitative estimation of concentration of unknown solution by titrating it…
Q: What is the concentration of Ca²* in solution that is prepared by mixing 50 ml 0.2 M Ca²+ with 50 ml…
A:
Q: Ex(1): In the analysis for chloride. The sample weighed (0.8732 gm) and the AgCI (p.p.t) from the…
A: AgCl contains 1 silver atom and 1 chlorine atom, so molar mass of AgCl, =1Atomic weight of…
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
- The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of Pd(II) with 2.44 10-4 M Nitroso R(O. W Rollins and M. M. Oldham, Anal. chem .,1971, 43, 262, DOI: 10.1021/ac60297a026). Calculate the concentration of the Pd(II) solution, given that the ligand-to-cation ratio in the colored product is 2:1A foot powder sample containing Zn was dissolved on 50.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (α= 3.61x109, KKzny2 = 3.2 x 1016). The pZn in the sample is:The Cr plating on a surface that measured 3.00 cm x 4.00 cm was dissolved in HCl. The pH was suitably adjusted, and 10.19 mL of 0.01441 M EDTA was then introduced. The excess reagent required a 2.91-mL back-titration with 0.007171 M Cu2+. Calculate the average weight (in mg) of Cr (51.9961 g/mol) on each square centimeter of surface.
- The Tl in a 9.76-g sample of rodenticide was oxidized to the trivalent state and treated with an unmeasured excess of Mg/EDTA solution. The reaction is Tl+3 + MgY-2 → TlY- + Mg+2 Titration of the liberated Mg2+ required 15.34-mL of 0.08560 N EDTA. The type of titration involved in the assay is ___ (direct/indirect/residual) and the percentage of Tl2SO4 in the sample is ____%. Molecular mass: Tl2SO4 = 504.8A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid CaCO3 in 100 mL dilute HCl. A 20.00 mL aliquot was taken for titration with EDTA consuming 32.00 mL of the titrant to reach the endpoint. Express the concentration of EDTA in molarity and in CaCO3 titer. MM Na2H2Y2•2H2O = 372.24 g/mole; MM CaCO3 = 100.09 g/moleA CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid CaCO3 in 100 mL dilute HCl. A 20.00 mL aliquot was taken for titration with EDTA consuming 32.00 mL of the titrant to reach the endpoint. Express the concentration of EDTA in molarity and in CaCO3 titer.MM Na2H2Y2•2H2O = 372.24 g/mole; MM CaCO3 = 100.09 g/mole
- A 60.00 mL of buffered solution (pH 10) containing Zn and Nit ions (from a chip sample) is analyzed using EDTA titration with EBT as indicator. The following data were recorded: M of EDTA = 0.05204 V of EDTA for Zn2+ =D41.97 V of EDTA for Ni2+ mL = 15.16 mL How many mmoles of Zn and Ni were present in the solution? If the weight of the chip is 1.000 g, give the % Zn and % Ni in the original sample.A water sample was tested for water hardness. A 50.00 mL sample, prepared and buffered to pH 10, required 23.55 mL of 0.0250 M EDTA. A second 50.00 mL aliquot, prepared with NaOH, was titrated with 14.53 mL of the same EDTA solution. a. Calculate the total hardness of the water sample, express in ppm CaCO3Five white, 500-mg uncoated ascorbic acid (AA) tablets with an average weight of 0.6100-g were pulverized in a mortar. A sample of the powdered ascorbic acid weighing 0.4610-g was placed in an iodine flask and was dissolved in 50-mL H2SO4 then 5-g of KBr was added to the resulting solution. The solution was titrated with 46.73-mL of 0.0152 M STD. KBrO3 to reach a faint yellow endpoint then 3-g KI and 5-mL Starch TS. The blue color solution is then titrated with 2.78-mL of 0.1047 M STD. Na2S2O3 to reach the disappearance of the blue iodostarch complex. MW: KBrO3 = 167.0 ; KIO3 = 214.0 ; Na2S2O3 = 158.11 ; C6H8O6 = 176.12 Compute the milligrams of pure AA per tablet from the assay. None of the choices 349.7 mg 264.3 mg 462.7 mg
- A 0.3045 g of CaCO3 primary standard was dissolved using concentrated HCl, evaporated to incipient dryness and quantitatively transferred to a 250 mL volumetric flask, and diluted to mark. A 10 mL of aliquot was then transferred to an Erlenmeyer flask, together with 5mL buffer and 5 drops of EBT indicator, and was used to standardize the EDTA titrant. The solution turned blue after the addition of 24.10 mL of EDTA. A blank correction was performed and was determined to be 0.4 mL. What is the concentration of EDTA obtained (MW CaCO3 = 100.0869 g/mol)?The Tl in a 9.76-g sample of rodenticide was oxidized to the trivalent state and treated with an unmeasured excess of Mg/EDTA solution. The reaction is Tl+3 + MgY-2 → TlY- + Mg+2 . Molecular mass: Tl2SO4 = 504.8 a. Titration of the liberated Mg2+ required 13.34-mL of 0.03560 N EDTA. The type of titration involved in the assay is (direct/indirect/residual) ______? b. percentage of Tl2SO4 in the sample is __________ %?A 0.3045 g of CaCO3 primary standard was dissolved using concentrated HCl, evaporated to incipient dryness, and quantitatively transferred to a 250 mL volumetric flask and diluted to mark. A 10 mL of aliquot was then transferred to an Erlenmeyer flask, together with 5mL buffer and 5 drops of EBT indicator, and was used to standardize the EDTA titrant. The solution turned blue after the addition of 24.10 mL of EDTA. A blank correction was made and was determined to be 0.4 mL. [Analysis] A 30 mL unknown water sample was treated with 37.6 mL of EDTA. A blank correction was made and was determined to be 0.4 mL. What is the concentration of Ca2+ (40.0780 g/mol) in ppm?