Q3 - The homogeneous bar AB have diameters 190mm when subjected to an axial tensile load of 34KN. have length 322mm the new length is 321.8mm. Find (Stress, Strain, Youngs modulus and factor of safety if the allowable working stress is 0,43MN?
Q: Q3\ The cantilevered bar shown in the fig. made from steel Cold-drawn with (Sy = 280 MPa) and is…
A:
Q: 2. A bronte bar is fastened between a steel bar and an aluminum bar as shown in Figure. Aaial foads…
A:
Q: The 0.06R (mm)-diameter bar is made of a brittle material with the ultimate strengths of 0.15R MPa…
A: d=.06R mm where R=993 d=.06×993=59.58 mmσut=.15R Mpa σut=.15×993 Mpa=148.95 Mpa Bending moment and…
Q: mple 4.3 (Numerical problem on thick cylinder subjected to internal urel: A thick cylinder of…
A: Answer: The thickness required of thick cylinder is 20.71 mm.
Q: Using the maximum-shear-stress (MSS) theory determine the factor of safety for a bar of AISI 1020…
A:
Q: 3-84* The cantilevered bar in the figure is made from a ductile material and is statically loaded…
A: Ans.(a) . Bending stress and pansverse stress is will bemaximum at the outer surface(spear stress…
Q: For the assembly shown in Figure.(5). If the stress in the steel rod become (120+b) Mpa when the…
A:
Q: Using the maximum-shear-stress (MSS) theory determine the factor of safety for a bar of AISI 1020…
A: Q) Given data σx = 170 MPa σy = 90 MPafor AISI 1020 carbon steel σyt = 350 MPaTo…
Q: A load Pis supported by a structure consisting of rigid bar ABC, two identical solid bronze (E -…
A:
Q: Two plates 20 mm thickness are fastened by a number of 25 mm diameter rivets, a tensile load of 500…
A:
Q: If the allowable stress of a revolving steel is 150 MPa, what is the equivalent angular velocity…
A: “Since you have asked multiple question, we will solve the first question for you. If youwant any…
Q: 1. The lap joint is fastened with four %-in-diameter rivets. The working stresses are 14 ksi for the…
A: The maximum safe axial load that can be applied to the joint is P = 24.74 kips.
Q: p. A steel 150mm long, 75mm external di bronze tube of the same length, 50mm external diameter and…
A: GIVENls=150 mmlb=150 mmDs=75 mmds=50 mmDb=50 mmdb=25 mmP=50 kN=50×103NEsteel=206 GN/m2Ebronze=95…
Q: Given: A steel rod (A= 150 mm?) is stretched between two fixed points with a tensile load of 5000 N…
A:
Q: Figure: Circular prismatic rods with negative torques at each end. The circular rod shown has an…
A:
Q: A hollow aluminum cylinder made of 2014-T4 has an outside diameter of 2.50 in. and a wall thickness…
A: Given data for aluminum cylinder 2014-T4
Q: Figure shows a tie bar made of steel. When bolted between A and B double brackets, it is to be…
A: Given Data, P= Tensile load in the bar = 100 KN The bolt is of double brackets, so the shear load…
Q: 2. A hollow cylinder 2 m long has an outside diameter of 50mm and inside diameter of 30mm. If the…
A:
Q: A solid steel shaft of radius b is to be pressed into a wrought iron hub of outer radius c and…
A: A solid steel shaft of radius b is to be pressed into a wrought iron hub of outer radius c and…
Q: Jason took a steel rod, 15.29-mm in diameter, and held snugly (but without any initial stress)…
A: Given: The diameter of rod, D = 15.29 mm The coefficient of thermal expansion, α = 13.6x10-6 mm/mmoC…
Q: Q4) In buckling experiment a steel column ( E-210 Gpa) was examined in pin-fixed method. It endured…
A: Givensteel columnE=210…
Q: Ex 5.2: Calculate the lateral strain for a mild steel rod subjected to an axially load causing an…
A: Given data : The value of axial strain is given in question . Axial strain is strain along the…
Q: Given the shear modulus(G) for aluminum as 2.4e+10 N/m2 and the shear strain is given as 6e-5. What…
A: From hook's law Shear stress is directly proportional to shear strain within elastic limit
Q: For the assembly shown in Figure.(5). If the stress in the steel rod become (170) Mpa when the…
A:
Q: Rod of diameter 20 mm is loaded with 5kN tension force. What is the magnitude of stress in the rod?
A: Given, Diameter of rod = d = 20 mm Force applied to rod = F = 5 kN = 5000 N Cross-sectional area…
Q: answer as soon as possible
A: The eccentric load is acting on the cube. Due to this, there will two types of stress generated…
Q: Imagine that a long steel wire hangs vertically from a high-altitude balloon.(a) What is the…
A:
Q: Based on the figure below. Find the largest force P that can be applied if the working compressive…
A:
Q: Q1: For the problem in Figure (1), determine maximum allowable load P such that maximum flexural…
A:
Q: The figure shows a horizontal steel bar of thickness h loaded in steady tension and welded to a…
A: Given data: b=49 mmd=48 mmh=5 mmτallow=148 MPa Need to determine the allowable force.
Q: A steel bar of diameter 1cm and length 10cm is made of steel E=200Gpa and yield strength of 300Mpa…
A:
Q: PROBLEM 3 Steel: A = 500 mm ,= 120 MPa 1.8 Find the maximum allowable value of P for the column. The…
A: The normal stress developed inside a member when acted upon by an axial force ca be calculated using…
Q: A cantilever hollow circular bar 5mm thick with inside diameter of 75mm is subjected to a torque of…
A: Given Data: The thickness of the bar is, t=5 mm. The inside diameter of the bar is, d=75 mm. The…
Q: For the assembly shown in Figure.(5). If the stress in the steel rod become (120+b) Mpa when the…
A:
Q: A tensile load of 6 kN at 25 C was applied to a steel rod stretching between two rigid walls as…
A: Given: F= 6 kN T=25°Cα=12.2 μm/(m°C)E=200 GPaσ=150 MPa
Q: A steel rod is stretched between two walls. At 20C, the tensile force in the rod is 5000N. If the…
A:
Q: A 60 mm diameter bar.carries an axial tensile load of 180 kN. Find the normal and tangential stress…
A: given data: diameter(d)=60mmtensile load(F)=180KN
Q: A hollow compression member with circular cross section having outer diameter 2 times the inner…
A:
Q: For the rod in the figure, an allowable stress of 10 ksi, calculate the maximum torque T which can…
A:
Q: A brittle material made of ASTM grade 30 cast iron has ultimate strength in tension of 31 kpsi and…
A: given data- Ultimate strength in tension- 31 kpsi Ultimate strength in compression- 109 kpsi σx=20…
Q: Find factor of safety if the Ultimate Stress of a ductile material is 250.94 MPa. If the material is…
A:
Q: Example 3.8. A lever is keyed to a shaft of 100 mm diameter. The width of the key is 12 mm and the…
A:
Q: 120 mm- The thrust bearing supports a load P = 275KN. Find a. The tensile stress in the rod b. The…
A:
Q: Q) In Fig.(1), the shaft is subjected to a reversed load P = (2700 to - 900) N. Find the length (L),…
A:
Q: A solid circular shaft OABC with a diameter of 30 mm is supported at bearing O and B, and subjected…
A:
Q: For a steel beam loading, the maximum normal compressive stress is - 6 MPa, maximum normal tensile…
A:
Q: Q1) A steel bolt, 2.5 cm in diameter, carries a tensile load of 40 kN. Estimate the average tensile…
A:
Step by step
Solved in 2 steps with 2 images
- A circular copper bar with diameter d = 3 in. is subjected to torques T = 30 kip-in. at its ends. Find i lie maximum shear, ion si le. and compressive stresses in the tube and their corresponding strains. Assume that G = 6000 ksi.Solve the preceding problem if the diameter is 480 mm, the pressure is 20 MPa, the yield stress in tension is 975 MPa, the yield stress in shear is 460 MPa, the factor of safety is 2,75, the modulus of elasticity is 210 GPa, Poissorfs ratio is 0.28, and the normal strain must not exceed 1190 x 10" . For part (b), assume that the tank thickness is 8 mm and the measured normal strain is 990 x 10~ .Two sections of steel drill pipe, joined by bolted flange plates at Ä are being tested to assess the adequacy of both the pipes. In the test, the pipe structure is fixed at A, a concentrated torque of 500 kN - m is applied at x = 0.5 m, and uniformly distributed torque intensity t1= 250 kN m/m is applied on pipe BC. Both pipes have the same inner diameter = 200 mm. Pipe AB has thickness tAB=15 mm, while pipe BC has thickness TBC= 12 mm. Find the maximum shear stress and maximum twist of the pipe and their locations along the pipe. Assume G = 75 GPa.
- (a) Solve part (a) of the preceding problem if the pressure is 8.5 psi, the diameter is 10 in., the wall thickness is 0,05 in., the modulus of elasticity is 200 psi, and Poisson's ratio is 0.48. (b) If the strain must be limited to 1.01, find the maximum acceptable inflation pressureA hollow, circular, cast-iron pipe (Ec =12,000 ksi) supports a brass rod (Ec= 14,000 ksi} and weight W — 2 kips, as shown. The outside diameter of the pipe is dc= 6 in. (a) If the allowable compressive stress in the pipe is S00O psi and the allowable shortening of the pipe is 0.02 in., what is the minimum required wall thickness trmm? (Include the weights of the rod and steel cap in your calculations.) (b) What is the elongation of the brass rod Srdue to both load Wand its own weight? (c) What is the minimum required clearance h?A solid circular bar of steel (G = 78 GPa) transmits a torque T = 360 N - m. The allowable stresses in tension, compression, and shear arc 90 MPa, 70 MPa, and 40 MPa, respectively. Also, the allowable tensile strain is 220 x 10-6, Determine the minimum required diameter d of the bar, If the bar diameter d = 40 mm, what is Tmax?
- An aluminum bar has length L = 6 ft and diameter d = 1.375 in. The stress-strain curse for the aluminum is shown in Fig. 1.34. The initial straight, line part of the curve has a slope (modulus of elasticity) of 10.6 × 106 psi. The bar is loaded by tensile forces P = 44.6 k and then unloaded. (a) That is the permanent set of the bar? (b) If the bar is reloaded. what is the proportional limit? hint: Use the concepts illustrated in Figs. l.39b and 1.40.- A specimen used in a coupon test has norm al stress ??. = 15 MPa (see figure). Using Mohr’s circle, find the state of stress on the element oriented at angle ? = 20° and show the full stress state on a sketch of a properly oriented element.Repeat Problem 2.3-18, but assume that the bar is made of aluminum alloy. If P2= 200 kN, what is P1so that displacement
- A solid copper bar of circular cross section has length L = 1.25 m and shear modulus of elasticity G = 45 GPa. The bar is designed to carry a 250 N · m torque acting at the ends. If the allowable shear stress is 30 M Pa and the allowable angle of twist between the ends is 2.5°, what is the minimum required diameter?Solve the preceding problem if the internal pressure is 3,85 MPa, the diameter is 20 m, the yield stress is 590 MPa, and the factor of safety is 3.0. (a) Determine the required thickness to the nearest millimeter. (b) If the tank wall thickness is 85 mm, what is the maximum permissible internal pressure?A circular tube AB is fixed at one end and free at the other. The tube is subjected to concentrated torques as shown in the figure. If the outer radius of the tube is 1.5 in, and the thickness is 3/4 in., calculate the strain energy stored in the tube. Let G= 11,800 ksi.