Q4// A 6-pole, 900 r.p.m lap-wound de series generator has 720 conductors, supplies a load 22 KW at a terminal voltage 220 V and the power generated 24 KW, calculates: 1- The flux per pole. 2- The armature voltage drops if the armature resistance is 0.05 2. 3-The generated e.m.f if the speed is decreased by 20% and the field current is unaltered.

Q4// A 6-pole, 900 r.p.m lap-wound de series generator has 720 conductors, supplies a load 22 KW at a terminal voltage 220 V and the power generated 24 KW, calculates: 1- The flux per pole. 2- The armature voltage drops if the armature resistance is 0.05 2. 3-The generated e.m.f if the speed is decreased by 20% and the field current is unaltered.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A long-shunt, four pole, 1500-W, 250-V, duplex wave-wound DC compound generator with the rated speed of 500 r.p.m., has a shunt field resistance of 100 Ω, a series field resistance of 0.05 Ω and an armature resistance of 0.2 Ω. If the flux per pole is 48.798 mWb and a total of 620 conductors, calculate the following: (a) the generated voltage, (b) the field currents, (c) the power generated in the armature.
A 35 kW, 400 V, short shunt, compound dc generator has a full load efficiency of 85 %. If the resistance of the armature and interpole is 0.35 ohm and that of the series and shunt fields are 0.15 ohm and 220 ohms respectively. Calculate the following: Output of the prime mover = kW Power developed in the armature = kw Total Copper Losses = kw Combined bearing friction, windage and core loss = kw
A 1500 kW, 550 V, 16 pole generator runs at 150 rev. per min. What must be the useful flux if there are 2500 conductors lap-connected and the full-load copper losses being 25 kW? Calculate the area of the pole shoe if the gap density has a uniform value of 0.9 wb/m2 and find the no-load terminal voltage, neglecting armature reaction and change in speed.
A long shunt compound generator delivers 100 A at 250 V. The armature, shunt field and series field resistances are 0.02 Ohms, 50 Ohms and 0.05 Ohms respectively. If the Break Horse Power (BHP) or the power developed by the shaft torque of the driving engine is 40, determine the stray loss.
. When a self-excited compound DC generator supplies load, the terminal voltage is not the same as the generated emE Why? a) voltage drop across the armature resistance will reduce the voltage available at the load terminals b) where there is a series field, voltage drop across the series field resistance will reduce the voltage available at the load terminals c) both "a" and "b" d) neither "a" nor "b"
A separately excited DC shunt generator produces a no-load voltage of 150 Vdc at 1200 RPM. If the armature resistance is 3 Ohms, calculate the output voltage under the following conditions: (Note all calculations for each problem are to be performed from the base values given above). a) The speed is reduced to 875 RPM. Vout = __________________ b) The field current is increased by 22% (assume a linear field current/flux relationship). Vout = __________________ c) The speed is increased to 1738 RPM Vout = __________________ d) The field current is reduced by 12% and the speed is increased to 1600 RPM Vout = _________________
A 500 V, 250 kW, long shunt compound generator induces an e.m.f. of 480 V whenrunning at 1000 r.p.m. no load. On full load the spped of the machine drops to 975r.p.m. the flux increases by 15% and the terminal voltage rises to 500 V. If theseries and shunt field resistances are 0.02 ohm and 100 ohms respectively,calculate the armature resistance. Assume a voltage drop of 1V per brush.[Ans.
A series generator having a combined armature and field resistance of 0.4 ohm usrunning at 1000 rpm and delivering 5.5 kW at a terminal voltage of 110 V. If thespeed is raised to 1500 rpm and load adjusted to 10 kW, find the new terminalvoltage. Assume the machine is working on straight line portion of magnetizationcharacteristics.
A 250 V shunt generator has a full load armature current of 40 A, under these conditions the losses are: FW = 200 watts, shunt field = 100 watts, core = 260 watts, brush contact = 120 watts, armature copper = 400 watts. For operation at maximum efficiency, when the constant losses are equal to those losses that vary as the square of the load, calculate the maximum efficiency.
A 500-V, wave-wound, 750 r.p.m. shunt generator supplies a load of 195 A. The armature has 720 conductors and shunt field resistance is 100 Ω. Find the demagnetising amp-turns/pole if brushes are advanced through 3 commutator segments at this load. Also, calculate the extra shunt field turns required to neutralize this demagnetisation.
An 8-pole dc generator has 500 armature conductors, and useful flux of 0.05 Wb perpole. What will be the emf generated if it is lap connected and runs at 1200 rpm? Whatmust be the speed at which it is to be driven to produce the same emf if it is waveconnected and the flux is reduced to 80% of its value when lap connected?
Dc machines A separately excited D.C. generator has an armature circuit resistance of 0.1 ohms. And the total brush-drop is 2 V. When running at 1000 r.p.m., it delivers a current of 100 A at 250 V to a load of constant resistance. If the generator speed drop to 700 r.p.m., with field-current unaltered, find the current delivered to load.