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Q(Lost by food)=Q(gained by water) Q(gained by water) = m*c*T Where, m- mass of water in grams c- specific heat capacity of water (1cal/g °C) T- change in temperature (C)

Q(Lost by food)=Q(gained by water) Q(gained by water) = m*c*T Where, m- mass of water in grams c- specific heat capacity of water (1cal/g °C) T- change in temperature (C)

Basic Clinical Laboratory Techniques 6E
Basic Clinical Laboratory Techniques 6E
6th Edition
ISBN:9781133893943
Author:ESTRIDGE
Publisher:ESTRIDGE
Chapter3: Basic Hemostasis
Section3.3: Principles Of Coagulation Testing
Problem 1CS
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Please show computation for calories and cal/gm

Q(Lost by food)=Q(gained by water) Q(gained by water) = m*c*T Where, m- mass of water in grams c- specific heat capacity of water (1cal/g °C) T- change in temperature ("C) mL to grams mLx Density of water g/mL density of water at 30°C is 0.995646 8mL (0995646 g/mL) = 7.965168g or 8g
Transcribed Image Text:Q(Lost by food)=Q(gained by water) Q(gained by water) = m*c*T Where, m- mass of water in grams c- specific heat capacity of water (1cal/g °C) T- change in temperature ("C) mL to grams mLx Density of water g/mL density of water at 30°C is 0.995646 8mL (0995646 g/mL) = 7.965168g or 8g
Temp. Differen Initial Final mL Substance Weight calories çal/gm Temp Temp Water се Peanut 0.3g 29°C 85°C 56 °C 8 ml 1 448 1493 0.3g 29°C 79°C 50 °C 8 ml 400 1333 0.3g 29°C 82°C 53 °C 8 ml 3 424 1413
Transcribed Image Text:Temp. Differen Initial Final mL Substance Weight calories çal/gm Temp Temp Water се Peanut 0.3g 29°C 85°C 56 °C 8 ml 1 448 1493 0.3g 29°C 79°C 50 °C 8 ml 400 1333 0.3g 29°C 82°C 53 °C 8 ml 3 424 1413
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