Question 1: The circuit below shows a reactor being disconnected from its supply. During the process of opening, the circuit breaker reignites but interrupts the reignition current at the first zero of the high frequency current, trapping energy in L2 Compute the peak voltage subsequently appearing across the reactor as a consequence of this trapping of energy. - L1 = 15mH L2 = 352mH C= 3.2nF

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter21: Resistive-capacitive Series Circuits
Section: Chapter Questions
Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...
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Question 1:
The circuit below shows a reactor being disconnected from its supply.
During the process of opening, the circuit breaker reignites but interrupts the reignition current at the
first zero of the high frequency current, trapping energy in L2
Compute the peak voltage subsequently appearing across the reactor as a consequence of this trapping
of energy.
L1 = 15mH
L2 = 352mH
C= 3.2nF
CB
LI
Vs
Transcribed Image Text:Question 1: The circuit below shows a reactor being disconnected from its supply. During the process of opening, the circuit breaker reignites but interrupts the reignition current at the first zero of the high frequency current, trapping energy in L2 Compute the peak voltage subsequently appearing across the reactor as a consequence of this trapping of energy. L1 = 15mH L2 = 352mH C= 3.2nF CB LI Vs
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