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Social ScienceQuestion 15 of 29>A mixture of hydrocarbons contains 40.0% heptane, C,H,, 14.6% nonane, COH2and 45.4% octane, C, H8 The mixutre is16'combusted in an excess of oxygen. What mass of CO, is generated from the combustion of 10.5 kg of the mixture?2kgmass of CO,:helpcontact usprivacy policyterms of useabout uscareers
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Question 15 of 29> A mixture of hydrocarbons contains 40.0% heptane, C,H,, 14.6% nonane, COH2 and 45.4% octane, C, H8 The mixutre is 16' combusted in an excess of oxygen. What mass of CO, is generated from the combustion of 10.5 kg of the mixture? 2 kg mass of CO,: help contact us privacy policyterms of use about us careers
Expert Answer
Balanced chemical equation for the combustion of heptane, nonane and octane is,
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>7 Со, + 8 H,о 16 9 СО, + 10 Н,О С,Н + 14 О, 20 2 С,Н + 25 О, 16 СО, + 18 Н,О 18
Number of moles of heptane, nonane and octane can be calculated as follows,
1 kg = 1000 g
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- Неptane 40 x 10.5 kg 100 Mass 40.0% of 10.5 kg 4.2kg 4200 g 4200 g 41.91 mol C,H16 No. of moles = 100.21 g/mol .Nonane 14.6 x10.5 kg 1.533 kg 1533 g 100 Mass 14.6% of 10.5 kg 1533 g 19.96 mol C,H20 No. of moles = 128.2 g/mol .Octane 45.4 -x 10.5 kg 100 Mass 45.4% of 10.5 kg 4.767 kg 4767 g 4767 g 41.73 mol C H18 No. of moles _ 114.23 g/mol
Number of moles CO2 reacted with heptane, nonane a...
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1 mol heptane reacts to give 7 moles of CO2 is No. of mol of CO2 formed by reacting with 41.91 mol C,H16 7 mol CO2 293.37 mol CO, 41.91 mol C,H16X 1 mol C,H16 1 mol nonane reacts to give 9 moles of CO2 No. of mol of CO, formed by reacting with 19.96 mol C,H16 is 9 mol CO2 1 mol C,H20 179.64 mol CO2 19.96 mol C,H20 2 mol octane reacts to give 16 moles of CO2 is No. of mol of Co, formed by reacting with 41.73 mol C,H6 16 mol CO2 2 mol CgH18 333.84 mol CO, = 41.73 mol C,Hg X-
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