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A cork popper. To entertain children between the ages of 2 and 90, Daniel Harris enjoys popping corks from bottles containing vinegar and baking soda. He pours about 50 mL of vinegar into a 500‑mL plastic bottle. Then, he wraps about 5 g of baking soda (which is sodium bicarbonate, NaHCO3 in one layer of tissue and drops the tissue into the bottle. He places a cork tightly in the mouth of the bottle and steps back. The chemical reaction generates CO2(g) that pressurizes the bottle and eventually bursts the cork into the air. Everyone smiles. CH3CO2Hacetic acid in vinegar+NaHCO3sodium carbonatein baking soda⟶CH3CO−2+Na++CO2(g)+H2O Find the formula mass of acetic acid and of sodium bicarbonate. acetic acid formula mass: 60 g/mol sodium bicarbonate formula mass: 84 g/mol   How many grams of acetic acid are required to react with 6.91 g of NaHCO3?

A cork popper. To entertain children between the ages of 2 and 90, Daniel Harris enjoys popping corks from bottles containing vinegar and baking soda. He pours about 50 mL of vinegar into a 500‑mL plastic bottle. Then, he wraps about 5 g of baking soda (which is sodium bicarbonate, NaHCO3 in one layer of tissue and drops the tissue into the bottle. He places a cork tightly in the mouth of the bottle and steps back. The chemical reaction generates CO2(g) that pressurizes the bottle and eventually bursts the cork into the air. Everyone smiles. CH3CO2Hacetic acid in vinegar+NaHCO3sodium carbonatein baking soda⟶CH3CO−2+Na++CO2(g)+H2O Find the formula mass of acetic acid and of sodium bicarbonate. acetic acid formula mass: 60 g/mol sodium bicarbonate formula mass: 84 g/mol   How many grams of acetic acid are required to react with 6.91 g of NaHCO3?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A cork popper. To entertain children between the ages of 2 and 90, Daniel Harris enjoys popping corks from bottles containing vinegar and baking soda. He pours about 50 mL of vinegar into a 500‑mL plastic bottle. Then, he wraps about 5 g of baking soda (which is sodium bicarbonate, NaHCO3 in one layer of tissue and drops the tissue into the bottle. He places a cork tightly in the mouth of the bottle and steps back. The chemical reaction generates CO2(g) that pressurizes the bottle and eventually bursts the cork into the air. Everyone smiles.

CH3CO2Hacetic acid in vinegar+NaHCO3sodium carbonatein baking soda⟶CH3CO−2+Na++CO2(g)+H2O

Find the formula mass of acetic acid and of sodium bicarbonate.

acetic acid formula mass: 60 g/mol
sodium bicarbonate formula mass: 84 g/mol
 
How many grams of acetic acid are required to react with 6.91 g of NaHCO3?
 
mass of acetic acid: 4.94 g
Use the ideal gas law to calculate how many liters of CO,(g) are generated when you mix 45.3 mL of vinegar with 6.91 g of NaHCO, if P = 1 bar and T = 300 K. volume of CO, : 0.940 If there is 0.500 L of air space in the bottle, what pressure can be generated to pop the cork? 31.458 pressure: bar Incorrect
Transcribed Image Text:Use the ideal gas law to calculate how many liters of CO,(g) are generated when you mix 45.3 mL of vinegar with 6.91 g of NaHCO, if P = 1 bar and T = 300 K. volume of CO, : 0.940 If there is 0.500 L of air space in the bottle, what pressure can be generated to pop the cork? 31.458 pressure: bar Incorrect
How many grams of acetic acid are required to react with 6.91 g of NaHCO,? mass of acetic acid: 4.94 g Vinegar contains ~5 wt% acetic acid. How many grams of vinegar are required to react with 6.91 g of NaHCO,? mass of vinegar: 98.8 The density of vinegar is close to 1.0 g/mL. How many milliliters of vinegar are required to react with 6.91 g of NaHCO, ? volume of vinegar: 98.8 mL
Transcribed Image Text:How many grams of acetic acid are required to react with 6.91 g of NaHCO,? mass of acetic acid: 4.94 g Vinegar contains ~5 wt% acetic acid. How many grams of vinegar are required to react with 6.91 g of NaHCO,? mass of vinegar: 98.8 The density of vinegar is close to 1.0 g/mL. How many milliliters of vinegar are required to react with 6.91 g of NaHCO, ? volume of vinegar: 98.8 mL
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