Question 3 Worksheet 13.6 #2 Consider the two-step mechanism below that has been proposed for the reaction of nitrous oxide to form nitrogen and oxygen gas to answer the following questi Step 1: N₂0 (9)→ N2 (9) + 0 (g) (slow) (fast) Step 2: N₂0 (g) + O (g) → N₂ (g) + O2(g) Net: 2 N₂0 (g) → 2 N₂ (9) + 02 (9) Part B: Based on the proposed rate law for the net overall reaction, what is the overall order of the reaction? Selected Answer: 1/2 order Worksheet 13.6 #2 X Consider the two-step mechanism below that has been proposed for the reaction of nitrous oxide to form nitrogen and oxygen gas to answer the following quest Step 1: N₂0 (g) → N₂ (g) + O(g) (slow) (fast) Step 2: N₂0 (g) + O (g) → N₂ (9) + 02 (9) Net: 2 N₂0 (g) → 2 N2 (9) + 02 (9) Part C: What intermediates/catalysts are present in this mechanism? Selected Answer: N₂O is a catalyst; there are no intermediates nesday, April 6, 2022 4:00:55 PM EDT Question 4
Question 3 Worksheet 13.6 #2 Consider the two-step mechanism below that has been proposed for the reaction of nitrous oxide to form nitrogen and oxygen gas to answer the following questi Step 1: N₂0 (9)→ N2 (9) + 0 (g) (slow) (fast) Step 2: N₂0 (g) + O (g) → N₂ (g) + O2(g) Net: 2 N₂0 (g) → 2 N₂ (9) + 02 (9) Part B: Based on the proposed rate law for the net overall reaction, what is the overall order of the reaction? Selected Answer: 1/2 order Worksheet 13.6 #2 X Consider the two-step mechanism below that has been proposed for the reaction of nitrous oxide to form nitrogen and oxygen gas to answer the following quest Step 1: N₂0 (g) → N₂ (g) + O(g) (slow) (fast) Step 2: N₂0 (g) + O (g) → N₂ (9) + 02 (9) Net: 2 N₂0 (g) → 2 N2 (9) + 02 (9) Part C: What intermediates/catalysts are present in this mechanism? Selected Answer: N₂O is a catalyst; there are no intermediates nesday, April 6, 2022 4:00:55 PM EDT Question 4
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.65PAE
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