QUESTION 40 According to the following reaction, how many moles of aluminum bromide should form when 1.95 moles of aluminum nitride reacts with 6.16 moles of sodium bromide? AIN + 3 NaBr -> AIBr3 + NazN

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter4: Stoichiometry Of Chemical Reactions
Section: Chapter Questions
Problem 42E: Write the balanced equation, then outline the steps necessary to determine the information requested...
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QUESTION 37
Which are spectator ions in the following aqueous reaction (remember that insoluble ionic compounds do not split apart in soliution):
NaCI
AGNO3
NaNO3 + AgCl
->
O All are spectator ions
CI"
NO3
Na+
Ag*
QUESTION 38
According to the following reaction, how many moles of lithium sulfide should be needed to produce 13.593 moles of lithium phosphide?
3 Li2S
Mg3P2 -> 2 LigP +3 MgS
QUESTION 39
According to the following reaction, how many moles of lithium sulfide should be needed to produce 2.845 moles of magnesium sulfide?
3 LizS + M93P2 -> 2 LigP + 3 MgS
QUESTION 40
According to the following reaction, how many moles of aluminum bromide should form when 1.95 moles of aluminum nitride reacts with 6.16 moles of sodium
bromide?
AIN + 3 NaBr -> AIBr3 + NazN
Transcribed Image Text:QUESTION 37 Which are spectator ions in the following aqueous reaction (remember that insoluble ionic compounds do not split apart in soliution): NaCI AGNO3 NaNO3 + AgCl -> O All are spectator ions CI" NO3 Na+ Ag* QUESTION 38 According to the following reaction, how many moles of lithium sulfide should be needed to produce 13.593 moles of lithium phosphide? 3 Li2S Mg3P2 -> 2 LigP +3 MgS QUESTION 39 According to the following reaction, how many moles of lithium sulfide should be needed to produce 2.845 moles of magnesium sulfide? 3 LizS + M93P2 -> 2 LigP + 3 MgS QUESTION 40 According to the following reaction, how many moles of aluminum bromide should form when 1.95 moles of aluminum nitride reacts with 6.16 moles of sodium bromide? AIN + 3 NaBr -> AIBr3 + NazN
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