Question 2: The reaction shown is not balanced. What else is missing in the overall equation?hydroxide (-OH)ethanolwater (H2O)benzophenone Ashe went into the lab to set up the following reaction:OHstrong acidOHheatbenzopinacolmolar mass = 366.46 g/molbenzopinacolonemolar mass = 348.45 g/molThey found a procedure ahead of time that says the following:"Combine 100 mg of benzopinacol and 1 mL of acetic acid in a test tube. Add a small crystal of iodine (the solution should brown), and warm the test tube gently. Follow thereaction by TLC. When it is complete (just a few minutes), chill the reaction mixture and filter the resulting crystals. You may have to add some cold ethanol to have enoughliquid to filter. Wash the crystals with a little cold ethanol, then record a melting point and yield." (From Bell, Clark, and Taber)

Answered: OH strong acid ÓH heat benzopinacol…

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OH strong acid ÓH heat benzopinacol molar mass = 366.46 g/mol benzopinacolone molar mass = 348.45 g/mol

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter21: Synthesis Of N-butyl Bromide And T-pentyl Chloride

Section: Chapter Questions

Problem 1aQ

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Question 2: The reaction shown is not balanced. What else is missing in the overall equation?

hydroxide (^-OH)

ethanol

water (H₂O)

benzophenone

Ashe went into the lab to set up the following reaction:
OH
strong acid
OH
heat
benzopinacol
molar mass = 366.46 g/mol
benzopinacolone
molar mass = 348.45 g/mol
They found a procedure ahead of time that says the following:
"Combine 100 mg of benzopinacol and 1 mL of acetic acid in a test tube. Add a small crystal of iodine (the solution should brown), and warm the test tube gently. Follow the
reaction by TLC. When it is complete (just a few minutes), chill the reaction mixture and filter the resulting crystals. You may have to add some cold ethanol to have enough
liquid to filter. Wash the crystals with a little cold ethanol, then record a melting point and yield." (From Bell, Clark, and Taber)

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