Question 6A one-way within-groups ANOVA on 2 and 15 degrees of freedom results in an Fstatistic of 3.12. What decision should be made about the hypothesis based on thisstatistic?Reject the null hypothesis and conclude the independent variable has no effect.Fail to reject the null hypothesis because the Fstatistic does not exceed thecritical cutoff.Fail to reject the null hypothesis and conclude there is no effect of theindependent variable.Reject the null hypothesis and conclude there are differences among the levelsof the independent variable.

The one-way ANOVA test is used to compare the means of more than 2 groups. This test also used to…

Answered: Question 6 A one-way within-groups…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An automobile manufacturer claims that their van has a 46 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the MPG for this van. After testing 61 vans they found a mean MPG of 46.1 with a variance of 6.76 MPG. Is there sufficient evidence at the 0.01 level that the vans outperform the manufacturer's MPG rating? State the null and alternative hypotheses for the above scenario.
Question 2 There is a claim that drink driving has been very common in high ways. The Highway Police randomly caught 300 drivers for breath alcohol test and found that 14% of drivers have breath alcohol over the legal limit. At 4% level of significance, use the p-value approach to test the hypothesis that the percentage of drivers who are drink driving is more than 10%.
For an ANOVA comparing three treatment conditions, what is stated by the alternative hypothesis (H1)? Question 34 options: All three of the population means are different from each other None of the other choices is correct There are no differences between any of the population means At least one of the three population means is different from another mean
Question 3 Edex limited is a renowned agricultural chemical manufacturer in Australia. They conduct many research and development in the field of Agri and Horticulture. Company wanted to examine the effect of temperature on farming of their selected range of products. Company has produced following results based on their data gathering. 15° C 35 24 36 39 32 25° C 30 31 34 23 27 35° C 23 28 28 30 31 You are required to answer following questions; 1. State the null and alternative hypothesis for single factor ANOVA to test for any significant difference in the perception among three groups. 2. State the decision rule at 5% significance level. 3. Calculate the test statistic. 4. Based on the calculated test statistics, decide whether there are any significant differences between the yield based on the given temperature levels.
A researcher conducts a one-way ANOVA and obtains a p value of .02 (when alpha = .05). What can you conclude? a.The researcher rejects the null hypothesis in favor of an alternative hypothesis. b. The research made a Type I error. c. either A or B d. neither A nor B
QUESTION 18 A researcher notes that there seems to be a difference in the prevalence of high blood pressure among college-educated individuals who consume low amounts of processed foods and the prevalence of individuals who only have a high school education and consume high amounts of processed foods. Use the appropriate hypothesis to test for the independence of the two independent variables presented here at the 5% significance level to ensure confounding has not influenced the study’s results. Then, interpret your response. Diet Low in Processed Foods Normal BP High BP Total College Education 124 55 179 High School Education 69 152 221 Total 193 207 400 Diet High in Processed Foods Normal BP High BP Total College Education 64 85 149 High School Education 98 153 251 Total 162 238 400 The chi square value of 37.724 is higher than the chi square value of 3.84; therefore, we do not reject H0 at the 5% level and reject H1, which states that level…
5) In a bumper test, three test vehicles of each of three types of autos were crashed into a barrier at 5 mph, and the resulting damage was estimated. Crashes were from three angles: head-on, slanted, and rear-end. The data appears below. a) Use JMP to fit a two-way ANOVA to the data. Using a = 0.05 draw conclusions for the ANOVA. Make sure you state your conclusion in the context of the problem. b) Does there appear to be a need to include the vehicle type / crash angle interaction term? c) Use JMP to fit a two-way ANOVA with interaction to the data. Auto Angle Damage Goliath Head-On 700 Goliath Head-On 1400 Goliath Head-On 850 Goliath Slant 1430 Goliath Slant 1740 Goliath Slant 1240 Goliath Rear end 700 Goliath Rear end 1250 Goliath Rear end 970 Varmint Head-On 1700 Varmint Head-On 1650 Varmint Head-On 1630 Varmint Slant 1850 Varmint Slant 1700 Varmint Slant 1650 Varmint Rear end 860 Varmint Rear end 1550 Varmint Rear end 1250 Weasel…
1. If the F-value is smaller than the critical values in the F-table, which statement is NOT TRUE? a. The Tukey Method is no longer necessary. b. The Tukey Method will reveal overlapping clusters. c. The Tukey Method will reveal only one cluster for all the means. d. The independent variable does not influence the dependent variable. 2. In a correlated design (for ANOVA), which part of the variance is removed from F? a. Variance Between b. Variance Within c. Variance due to fluctuations or chance factors d. Variance due to pre-existing individual differences 3. One advantage of a correlated-groups design is that the effects of ---- have been removed. a. Individual differences b. Experimenter effects c. Subject bias effects d. Measurement error

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