Question 6. Inside a rigid container, initially filled with 2.5 kPa CO2 at 383.08K. Then excessive amount of NHCOONH4(S) is added inside and the volume of the solid is negligible Assume the only reaction inside the system is: NH2COONH4(S) 2 NH3 (g) + CO2 (g). After equilibrium, the total pressure of the system is 6.39 kPa. (a) At this temperature if Fe catalyst is added, the NH3 can decompose as: 2NH3 = N2 + 3H2 At 298K, this reaction A, G = -33kJ /mol, A,H = -92.4kJ/mol Assume A, H is constant and there was some other inert gas to keep the pressure at 100 kpa Calculate the partial pressure of N2, H2 and CO2 at equilibrium

Principles of Modern Chemistry
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ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter14: Chemical Equilibrium
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Question 6.
Inside a rigid container, initially filled with 2.5 kPa CO2 at 383.08K. Then excessive
amount of NH2COONH4(S) is added inside and the volume of the solid is negligible
Assume the only reaction inside the system is: NH2COONH4(S) 2 NH3 (g) +
CO2 (g). After equilibrium, the total pressure of the system is 6.39 kPa.
(a) At this temperature if Fe catalyst is added, the NH3 can decompose as:
2NH3 = N2 + 3H2
At 298K, this reaction A,G
= -33kJ/mol, A,H = -92.4kJ/mol
Assume A,H is constant and there was some other inert gas to keep the
pressure at 100 kpa
Calculate the partial pressure of N2, H2 and CO2 at equilibrium
Transcribed Image Text:Question 6. Inside a rigid container, initially filled with 2.5 kPa CO2 at 383.08K. Then excessive amount of NH2COONH4(S) is added inside and the volume of the solid is negligible Assume the only reaction inside the system is: NH2COONH4(S) 2 NH3 (g) + CO2 (g). After equilibrium, the total pressure of the system is 6.39 kPa. (a) At this temperature if Fe catalyst is added, the NH3 can decompose as: 2NH3 = N2 + 3H2 At 298K, this reaction A,G = -33kJ/mol, A,H = -92.4kJ/mol Assume A,H is constant and there was some other inert gas to keep the pressure at 100 kpa Calculate the partial pressure of N2, H2 and CO2 at equilibrium
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