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Question 8 Consider the electrochemical cell described by the following reaction at 310 K. The measured cell potential is 0.237 V. What is the concentration of iodide ion (in M) if there are 1.15 M of cadmium ions in the cell? 2Cul(s) + Cd(s) → Cd²+ + 21- +2Cu(s) (Use R = 8.314 J/mol-K; F = 96485 C/mol) Additional data: E° Cul/l-/Cu = -0.17 V E Cd2+/Cd = -0.403 V Express your answer with 2 decimal places and do not encode the units. If negative, include the sign in your encoded answer.

Question 8 Consider the electrochemical cell described by the following reaction at 310 K. The measured cell potential is 0.237 V. What is the concentration of iodide ion (in M) if there are 1.15 M of cadmium ions in the cell? 2Cul(s) + Cd(s) → Cd²+ + 21- +2Cu(s) (Use R = 8.314 J/mol-K; F = 96485 C/mol) Additional data: E° Cul/l-/Cu = -0.17 V E Cd2+/Cd = -0.403 V Express your answer with 2 decimal places and do not encode the units. If negative, include the sign in your encoded answer.

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 110QRT
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Question 8 Consider the electrochemical cell described by the following reaction at 310 K. The measured cell potential is 0.237 V. What is the concentration of iodide ion (in M) if there are 1.15 M of cadmium ions in the cell? 2Cul(s) + Cd(s) → Cd²+ + 21¯ + 2Cu(s) (Use R = 8.314 J/mol-K; F = 96485 C/mol) Additional data: E° Cul/l-/Cu = -0.17 V E° Cd2+/Cd = -0.403 V Express your answer with 2 decimal places and do not encode the units. If negative, include the sign in your encoded answer.
Transcribed Image Text:Question 8 Consider the electrochemical cell described by the following reaction at 310 K. The measured cell potential is 0.237 V. What is the concentration of iodide ion (in M) if there are 1.15 M of cadmium ions in the cell? 2Cul(s) + Cd(s) → Cd²+ + 21¯ + 2Cu(s) (Use R = 8.314 J/mol-K; F = 96485 C/mol) Additional data: E° Cul/l-/Cu = -0.17 V E° Cd2+/Cd = -0.403 V Express your answer with 2 decimal places and do not encode the units. If negative, include the sign in your encoded answer.
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