Redraw the table below and then enter the number of electrons in each quantum level (n) for the following elements. If the quantum level does not contain any electrons, enter a “0” (zero). HINT: For each element in the table, arrange the electrons into the energy level diagram. Next, count the number of electrons in each quantum level (n). For each element in the table, electrons are placed into the energy level diagram. After doing so, you can count the number of electrons in each quantum level (n). Can you help me, please? How can I solve the n=1, n=2, n=3, n=4 for the hydrogen, magnesium, bromine, potassium?

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter6: Electronic Structure And The Periodic Table
Section: Chapter Questions
Problem 21QAP: What type of electron orbital (i.e., s, p, d, or f) is designated by an electron with quantum...
icon
Related questions
Question
100%

Redraw the table below and then enter the number of electrons in each quantum level (n) for the following elements. If the quantum level does not contain any electrons, enter a “0” (zero). HINT: For each element in the table, arrange the electrons into the energy level diagram. Next, count the number of electrons in each quantum level (n). For each element in the table, electrons are placed into the energy level diagram. After doing so, you can count the number of electrons in each quantum level (n).

Can you help me, please? How can I solve the n=1, n=2, n=3, n=4 for the hydrogen, magnesium, bromine, potassium?

Element
hydrogen (H)
magnesium (Mg)
bromine (Br)
potassium (K)
n=1
1
2
2
2
n = 2
0
8
8
8
n=3 n = 4
0
0
2
0
18
7
8
1
Note that the 4s orbital is lower in energy than the 3d
orbitals, therefore the 4s orbital will accept [one electron
before electrons are placed in the 3d orbitals.
Transcribed Image Text:Element hydrogen (H) magnesium (Mg) bromine (Br) potassium (K) n=1 1 2 2 2 n = 2 0 8 8 8 n=3 n = 4 0 0 2 0 18 7 8 1 Note that the 4s orbital is lower in energy than the 3d orbitals, therefore the 4s orbital will accept [one electron before electrons are placed in the 3d orbitals.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
Group 2 Elements
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Principles of Modern Chemistry
Principles of Modern Chemistry
Chemistry
ISBN:
9781305079113
Author:
David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning