Regular output capacity is 130 units per month. Regular cost per unit = K600. Overtime cost per unit K900. Beginning inventory is 0 units. We have the forecast of engine demand shown below: a) Develop a chase plan that matches the forecast. Calculate the cost of the plan. b) Develop a level plan that uses inventory to absorb fluctuations. Compare the costs of the level plan to the costs of the chase plan from Part (a). Inventory carrying cost per unit per month = 20. Backlog cost per unit per month = K900. There should be no backlog in the final month. Month Forecast 1 120 2 135 3 140 4 120 5 125 6 125 7 8 140 135 Total 1,040

Practical Management Science
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ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
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Question 3
Regular output capacity is 130 units per month. Regular cost per unit = K600. Overtime cost per unit
K900. Beginning inventory is 0 units. We have the forecast of engine demand shown below:
a) Develop a chase plan that matches the forecast. Calculate the cost of the plan.
b) Develop a level plan that uses inventory to absorb fluctuations. Compare the costs of the level
plan to the costs of the chase plan from Part (a). Inventory carrying cost per unit per month = 20.
Backlog cost per unit per month = K900. There should be no backlog in the final month.
Month
Forecast
1
120
2
3
135 140
4
120
End of assignment 1
5
125
6
125
7
140
=
8
135
Total
1,040
Transcribed Image Text:Question 3 Regular output capacity is 130 units per month. Regular cost per unit = K600. Overtime cost per unit K900. Beginning inventory is 0 units. We have the forecast of engine demand shown below: a) Develop a chase plan that matches the forecast. Calculate the cost of the plan. b) Develop a level plan that uses inventory to absorb fluctuations. Compare the costs of the level plan to the costs of the chase plan from Part (a). Inventory carrying cost per unit per month = 20. Backlog cost per unit per month = K900. There should be no backlog in the final month. Month Forecast 1 120 2 3 135 140 4 120 End of assignment 1 5 125 6 125 7 140 = 8 135 Total 1,040
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