Results: Part 1: Sensor reading Solution Step Initial Vol (ml) Final Vol (ml) Molarity Moles of Solute preparation 500 ml 500 ml 0.680 mol/L dilution 500 ml 700 ml 0.478 mol/L draining 700 ml 400 ml 0.478 mol/L evaporation 400 ml 250 ml 0.710 mol/L
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- Standardization of Sodium Thiosulfate Solution Primary Standard used: Potassium Dichromate Formula mass of 1o standard: __________________ % Purity of 1o standard: 99.80% Trials 1 2 3 Weight of K2Cr2O7 (g)Weight of K2Cr2O7 (g) 0.0315 0.0331 0.0380 Final Volume Reading Na2S2O3 (ml) 27.50 27.50 34.90 Initial Volume Reading Na2S2O3 (ml) 1.10 0.00 1.00 Net Volume Na2S2O3 used (ml) Molarity of Na2S2O3Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?Determine the concentration of linalool in a highly valued lavender essential oil. The peak areas of a series of standard solutions (calibrations standards) acquired from GC-MS (gas chromatography-mass spectrometry) is presented below. Concentration (mg/L) Peak area 0 201 25 5214 50 14658 75 23647 100 32657 125 42652 150 52478 QUESTION: Calculate the concentration of linalool in yourhighly valued lavender essential oil which returns a peak area of 27235.
- I would need help with these questions. The method referenced above was followed by a student and she got the following results: Caffeine Std. Conc. (ppm) Absorbance 100 1.806 50 0.899 40 0.724 30 0.545 20 0.365 10 0.183 Further, she analyzed an unknown sample and she got the following results: Sample # Absorbance 1 0.398 1. Graphically find the concentration in ppm and then calculate in mol/L of Caffeine in Sample #1? 2. Which solvent was used to extract Caffeine and why? Why is it necessary to do extraction three times? 3. Cuvettes used in this experiment were made from which material and why? 4. At what wavelength the Absorbance was measured?EX 2.Given-> Volume of Na+ = 500 ml Molarity of Na+= 0.0100M Molar mass of Na2CO3 = 105.99 gm/mole Millimole of Na+ = molarity × volume Number of millimole = 0.0100 × 500 = 5 millimole Na2CO3 ---> 2Na+ + CO32- Millimole of Na2CO3 = millimole of Na+/2 Millimole of Na2CO3 =5/2 = 2.5 millimole Mole of Na2CO3 = 2.5 × 10-3mole (1 mole = 10^3 millimole) Weight of Na2CO3 required = mole × molar mass = 2.5 × 10-3 × 105.99 =0.26 gm Hence, 0.26 gm Na2CO3 must dissolve in 500 ml of water.A 18 g of unknown organic sample was dissolve in 756 mL of benzene. The boiling point of benzene was increased by 3.36oC. As the first step of analysis, determine the moecular weight of the unknow sample? Kb of benzene= 2.64oC/m Bb of benzene = 80.09 oC density of benzene = 0.874 g/mL at 25 °C Answer in whole number, no units required.
- Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 2.29 1.41 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 50.37 49.39 49.84 Table 2. Titration data Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 2.29 1.41 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 50.37 49.39 49.84 Expected color at end point Volume of NaOH used (mL) 48.08 47.98 47.89 Compute for the ff: a. Average moles of acetic acid (mol)? b. Average molarity of acetic acid (M)? c. Average molarity of acetic acid (M)?SALT SOLUTION: Trial 1: Volume: 25 mLMass of 25mL solution: 29.824 gDensity: 1.2 g/mL Trial 2:Volume: 25 mLMass of 25 mL solution: 29.855 gDensity: 1.2 g/mL Trial 3:Volume: 25 mLMass of 25 mL solution: 29.816 gDensity: 1.2 g/mL METAL BAR: Method I - Trial 1:Mass of metal bar: 57.063 gVolume of metal bar: 6.7 cm^3Density of bar: 8.5 g/cm^3 Trial 2:Mass of metal bar: 57.063 gVolume of metal bar: 6.0 cm^3Density of bar: 9.5 g/cm^3 Trial 3:Mass of metal bar: 57.063 gVolume of metal bar: 6.0 cm^3Density of bar: 9.5 g/cm^3 Method 2 - Trial 1:Dimensions: diameter = 1.20 cm, height = 4.91 cmMass of metal bar: 57.063 gVolume of metal bar: 5.55 cm^3Density of bar: 10.3 g/cm^3 Trial 2:Dimensions: diameter = 1.20 cm, height = 4.95 cmMass of metal bar: 57.063 gVolume of metal bar: 5.60 cm^3Density of bar: 10.2 g/cm^3 Trial 3:Dimensions: diameter = 1.20 cm, height = 4.95 cmMass of metal bar: 57.063 gVolume of metal bar: 5.60 cm^3Density of bar: 10.2 g/cm^3 QUESTION - From your data, calculate the…From a 10-mL sample, a 1-mL aliquot was taken and diluted to 100mL. From this, a 5-mL aliquot was taken and diluted to 20mL.The final 20mL was found to have a concentration of 0.004M analyte X.What is the concentration of analyte X in the 10-mL sample?
- Table of caffeine standards concentration . Sample Conc, ppm Std1 16 Std2 32 Std3 48 Std4 64 Std5 80 If the volume used to make 100 mL of std 1 is 2 uL what is the concentration in M used to make std calibration curve ? The standards are going to be used to build calibration curve to analyze caffeine in an energy drink. if 500 mL of the energy drink has target of 400 mg , how will you prepare the sample if you need 10 mL for the analysis ? Caffeine MM=194.19 g/mol.Sample AnalysisSource of Water sample:Tap Water Molarity of Na2S2O3 1 2 3 0.0243 0.0245 0.0228 Average Molarity of Na2S2O3 0.0239 Trials 1 2 3 Volume of sample used 100.00 100.00 100.00 Final Volume Reading Na2S2O3 (ml) 6.70 10.00 13.10 Initial Volume Reading Na2S2O3 (ml) 3.40 6.70 10.00 Net VolumeNa2S2O3 used (ml) 3.30 3.30 3.10 mg O2 in sample ppm O2 in sample average ppm O2 in sampleMethodology: Make schematic diagram for the procedure below B. % SO3 determination Dry the soluble sulfate sample at 100° C for 1-2 hours, and cool in desiccator. Weigh out 0.5 – 0.7 g (± 0.3 mg) duplicates sample. Transfer to 400-mL beakers. Dissolve each in 200 mL of dist. H2O + 4 mL of 6 m HCl. Precipitant is prepared by dissolving 1.3 g BaCl2 ∙ H2O in 100 mL water. Filter if solution is not perfectly clear. Heat the BaCl2 solution and sulfate sample solution nearly to boiling, and then add the entire amount to the HOT sulfate sample solution while stirring vigorously. Wash stirring rod with distilled water and include washings in your final mixture. Digest by letting stand 1-2 hours. Overnight standing is acceptable. Filter through an ash less filter paper of fine porosity (Whatman no. 42). Slowly pour the supernatant liquid through the filter paper.