S. No. A B 1 Years C D Investment amount Price per share No. of mutual fund shares 2 2018 3 2019 4 2020 5 2021 3250 32 =B2/C2 3250 40 =B3/C3 3250 37 =B4/C4 3250 39 =B5/C5 6 7 a) Total amount invested =SUM(B2:B5) 8 b) Total number of mutual fund shares =SUM(D2:D5) 9 c) Average cost of each mutual fund share=(C2+C3+C4+C5)/4
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- 93.6g to ng and 93.6g to tons with the set up in the image possible show how to get the answer pleaseA 1.59 g sample containing KI was analyzed gravimetrically and 0.0538g of Barium Iodate was recovered... express the results of this analysis as percent posassium iodide.Obtain values from the pictures found in the procedure to complete the data table below.Remember to include units!A. Data:1 Mass empty beaker2 Mass beaker + Na2CO33 Mass Na2CO3 used4 Mass graduated cylinder + HCl(aq)5 Mass empty graduated cylinder6 Mass HCl(aq) used7 Total mass before rxn: beaker + Na2CO3 + HCl(aq)8 Mass beaker + salt solution after reaction9 Mass of CO2 generated by the reaction10 Mass of beaker + NaCl (after drying)11 Mass of NaCl Generated
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- balance this 2Al+2KOH+4H2SO4+24H2O----> ASApp 10 minsGiven the following data for Mass of test tube and stearic acid = 14.17 gMass of test tube = 11.40 gFreezing point of strearic acid = 69.59o CMass of weighing paper + naphthalene =1.230 gMass of weighing paper = 0.920 gFreezing point solution = 64.00o CKf = 4.5o C/m Determine the following1. mass of stearic acid in g (2 decimal places); 2.77g2. mass of naphthalene in g (2 decimal places); 0.31g3. freezing point depression (2 decimal places); 3.93oC4. molality of solution (3 significant figures); _____5. moles of naphthalene (3 significant figures); _____6. molar mass of naphthalene, experimentally (3 significant figures); _____7. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); _____using exactly 5.00 mL of 0.0400 M stock CuSO4 solution. Add 100 mL of water. Data for Part IMass of empty dish: 32.470 g empty dishVolume of 0.0400 M solution: 5.00 mL CuSO4 solution.Mass of dish and 0.0400 M solution: 37.497 g dish and solutionMass of dish and CuSO4 solid: 32.503 g dish and CuSO4 solidCalculations for Part I1. Calculate the mass of solution? 5.027 g 2. Calculate the mass of solid CuSO4 dissolved in the solution? 0.033 g 3. Calculate the number of moles of solid CuSO4 dissolved in the solution? 2.07 x 10-4 mol4. Calculate the mass of water evaporated from the solution? 0.0414 M5. Calculate the density of solution, (g solution/mL solution)?6. Calculate the % by mass, CuSO4 in solution (100 x g CuSO4/g solution)?7. Calculate the molality of solution (moles CuSO4/kg solvent)?8. Calculate the molarity of solution (moles CuSO4/L solution)?9. Given that the true molarity is 0.0400 M, calculate the percent error…