Sample is used to estimate the life expectancy for males in a certain county. Find the 99% confidence interval for a sample of size 51 with a mean of 45.8 years and a standard deviation of 15.3 years. Enter your answer as an open-interval (i.e., parentheses) accurate to one decimal place (because the sample statistics are reported accurate to one decimal place). 99% C.I. =

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A:

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Population standard deviation, sigma is 60.The z-critical value for 95% confidence interval is…

Q: How large a sample should be selected to provide a 99% confidence interval with a margin of error of…

A: Given,standard deviation(σ)=50margin of error (E)=10α=1-0.99=0.01α2=0.005Z0.005=2.58

Q: A small business ships specialty homemade candies to anywhere in the world. Past records indicate…

A: Solution-:  Here, is unknown so we use t-test Given: We find, (a) What is the standard error? (b)…

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A: Note- Part (a) is solved correctly, therefore I am giving the solution of the part (b) and part (c).…

Q: A postmix beverage machine is adjusted to release a certain amount of syrup into a chambe where it…

A: Formula : CI=point estimate ± ME

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A: Given Data : Sample Size, n = 30.0 Sample Mean, x̄ = 32.8 standard…

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A:

Q: The bottlers of a new fruit juice daily select a random sample of 12 bottles of the drink to…

A:

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A: a)   In this case, the population standard deviation is not given. In addition, the sample size is…

Q: The average daily volume of a computer stock in 2011 was u= 35.1 million shares, according to a…

A: Given data: Mean (u ) = 35.1 million shares Sample mean = 29.1 million shares Sample size (n) = 30…

Q: The local police department attempted to estimate average vehicle speeds along a strip of Main…

A: Standard error- is the standard deviation of its sampling distribution or an estimate of that…

Q: A random sample of 150 students has a grade point average with a mean of 2.86 and with a standard…

A: It is given that the sample size is 150, the mean is 2.86 and the standard deviation is 0.78.

Q: A statistics practitioner took a random sample of 50 observations from a population whose standard…

A: Given data ,n=50σ=23x=100a) Population mean with 90 %   The z-value at 90 % confidence is…

Q: The tolerable level of a certain pollutant is 16 mg/l. A researcher takes a sample of size n=50, and…

A:

Q: A researcher is interested in estimating the mean blood alcohol content (BAC) of people arrested for…

A: From the provided information, Sample size (n) = 250 Standard deviation (σ) = 0.065 Confidence level…

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A: n = 40 x̅ = 27.6 s = 12.2 Significance level (α) = 1 - 0.95 = 0.05

Q: The average daily volume of a computer stock in 2011 was u= 35.1 million shares, according to a…

A: Given: The average daily volume of computer stock in 2011 is μ=35.1 million shares. The sample…

Q: When preparing a national standardized test to be given to sixth graders, The Standard Test Company…

A: We have given that  Sample size n = 50 Sample mean = 135  Standard deviation = 20 95% confidence…

Q: Suppose that you wish to obtain a confidence interval for a population mean. Under the conditions…

A: Given The Pop. sd is unknown. The pop. is normally distributed. The sample size (n) is small.

Q: The mean blood sodium concentration of these 38 cases was 115 mmol/l, with standard deviation of 12…

A: Note:  Hey, since multiple questions are posted, we will answer first question for you. If you want…

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A: Here we've to test that average daily volume of a computer stock in 2011 was mu=35.1 So null…

Q: In a sample of 80 light bulbs, the mean lifetime was 1217 hours with a standard deviation of 52…

A: Solution: Note: Hello! As you have posted more than 3 sub parts, we are answering the first 3…

Q: The average daily volume of a computer stock in 2011 was u= 35.1 million shares, according to a…

A:

Q: Peter collects data on the music scores of 200 randomly selected concertos. The sample mean of this…

A: It is given that the mean is 85,252 and the standard deviation is 8,413.

Q: A random sample of 10 employees of a company was selected to estimate the mean one-way commute time…

A: Given Information :  A random sample of 10 employees of a company was selected to estimate the mean…

Q: The average daily volume of a computer stock in 2011 was u= 35.1 million shares, according to a…

A: Given that  The average daily volume of a computer stock in 2011 = (μ)=35.1 Sample size (n) = 30…

Q: e to construct a 90% confidence Interval to estimate the population mean annual income for people…

A: μ = 40416.5σ = 7545

Q: A bread shop owner wishes to find the 95% confidence interval of the true mean cost of special…

A: The formula for the sample size needed to estimate a population mean is

Q: A mobile phone manufacturer wishes to estimate how frequently their customers buy a new phone. They…

A: Solution: Let X be the random variable. From the given information, x-bar=1.9 years, S=1.2 and n=22.

Q: In a manufacturing process a random sample of 22 bolts manufactured has a mean length of 3.1 inches…

A:

Q: A random sample of 80 customers, who visited a department store, spent an average of $75 at this…

A: Solution: Given information: n= 80 Sample size x= $75  Sample mean σ= $16 Population standard…

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A: Given that x¯=30.8s=12.3n=30 degrees of freedom=n-1=30-1=29 confidence level is 95%. Significance…

Q: The average salary of 81 random employees in a certain financial sector was 3400 USD. From past…

A: Solutio

Q: In a study it was found out of a random sample of 30 there was a sample standard deviation of 2.4.…

A:

Q: How much money does the average professional football fan spend on food at a single football game?…

A:

Q: How large a sample should be selected to provide a  95% confidence interval with a margin of error…

A: It is given that the confidence level is 95% and the margin of error is 1. Assumed population…

Q: A random sample of 16 light bulbs has a mean life of 650 hours and a standard deviation of 32 hours.…

A: Mean = mu = 650 Standard deviation = sigma = 32 25.0 Sample size = 16 Therefore standard error of…

Q: The heights of a simple random sample of 400 male high school sophomores in a Midwestern state are…

A: Given info: The heights of a simple random sample of 400 male high school sophomores in a Midwestern…

Q: A random sample of 16 employees taken from the management level of the company gives a mean monthly…

A: Given that  Sample size = 16 , Mean = 17000 , Standard deviation = 5500

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given dataStandard deviation = 20Confidence interval = 0.95Significance level(α) = 1- 0.95 = 0.05n =…

Q: A cell phone company would like to estimate the average number of text messages received by American…

A:

Q: A tire manufacturer investigated the tread life of its tires. Samples of 10 tires driven 50,000…

A:

Q: An agriculture publication claims that the population mean of the birth weights for all Suffolk…

A: a) From the given information, The samples size is 35. The sample mean is 5.41.

Q: Find a 90% confidence interval for the mean if a sample of size 12 has a mean = 34.2 and the…

A: The sample size is 12, sample mean is 34.2, and sample standard deviation is 8.5. The degrees of…

Q: 1. A recent study stated that if a person smoked, the average of the number of cigarettes he or she…

A: Data given Population mean μ=14, n=40, sample mean x̄=18, s=6, level of significance ɑ=0.05

Q: The average daily volume of a computer stock in 2011 was u = 35.1 million shares, according to a…

A:

Q: The average daily volume of a computer stock in 2011 was u= 35.1 million shares, according to a…

A: The 95% confidence interval is (22.134, 32.066)

Q: A researcher wishes to estimate the average amount a college student makes over the summer. Assume…

A: (a)compute sample size  n  = (z a/2 *  s.d / me ) ^2z alpha/2 at 0.1 level of significance is =…

Q: The average salary of 81 random employees in a certain financial sector was 3400 USD. From past…

A: Population standard deviation=450 Sample size =81