sample of 153 was selected from a large population. 69% of the sample had a characteristic of interest. Calculate a 99% confidence interval estimate for the proportion of the population with the characteristic.

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A: Given that  List the five steps of hypothesis testing and explain the procedure and logic of each.

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Q: 6 A factory produces bars of chocolate that follow a Normal Distribution with a mean weight of 70g…

A: Mean(µ) = 70 Variance (σ2 ) = 9Standard deviations (σ) = √Varince(σ2)=√9 = 3X ~ N (µ, σ )= N(70, 3)

Q: 64 -32- 16 270-80 64 48-32-1 52-48-64-8090 -16 -48 64- 180 of83-9-8- e-8-9-38-8

A: From given figure ,by observing it we can drawn the following observations are:

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A: Here use  proportion test for 2 sample

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A: Mean(µ) = 175Standard deviations (σ) = 6X ~ N (µ, σ )= N(175, 5)

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Q: Mustration 21.4. Is the data given below consistent? N=1,000. (A)=500, KAB)=200, (BC)=250, (B)=550,…

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Q: Suppose the mean amount of cholesterol in eggs labeled “large” is 186  milligrams, with standard…

A: Given that  μ = 186 , ? = 7 , n = 144

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A: From the provided information, Mean (µ) = 40 Standard deviation (σ) = 6 X~N (40, 6)

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Q: - The p-value = (Please show your answer to 4 decimal places.)

A: Given that  Sample size n =11 Population mean =77