Sample Site C Final reading (mL) 1 accurate titration 2nd accurate titration 41.00 mL 40.10 mL Initial Reading (mL) 11.85 mL 10.95 Volume River water added to 29.15 cm3 = 0,02915 L 29.15cm 0.02915 the flask (L) Average volume River water added to the flask (L) 29.15 cm3 = 0,02915 L Calculate average moles of HCl in River water, mol Average concentration (M) of HCl in the River water. M = mol/L

Appl Of Ms Excel In Analytical Chemistry
2nd Edition
ISBN:9781285686691
Author:Crouch
Publisher:Crouch
Chapter9: Complexometric And Precipitation Titrations
Section: Chapter Questions
Problem 14P
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How do I solve for the bottom two boxes.

(Calculate average moles of HCl in River water, mol)

(Average concentration (M) of HCl in the River water. M=mol/L

2nd
accurate titration
Sample Site C
Final reading (mL)
st
1" accurate titration
41.00 mL
40.10 mL
Initial Reading (mL)
|1.85 mL
10.95
mL
Volume River water added to
29.15 cm3 = 0,02915 L
29.15cm 0.02915
the flask (L)
Average volume River water
added to the flask (L)
Calculate average moles of
HCl in River water, mol
29.15 cm3 = 0,02915L
Average concentration (M) of
HCl in the River water. M =
mol/L
Transcribed Image Text:2nd accurate titration Sample Site C Final reading (mL) st 1" accurate titration 41.00 mL 40.10 mL Initial Reading (mL) |1.85 mL 10.95 mL Volume River water added to 29.15 cm3 = 0,02915 L 29.15cm 0.02915 the flask (L) Average volume River water added to the flask (L) Calculate average moles of HCl in River water, mol 29.15 cm3 = 0,02915L Average concentration (M) of HCl in the River water. M = mol/L
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