Table 1. Titration data Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.48 1.89 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 49.32 49.06 49.93 Table 2. Titration data Table view List view Table 2. Titration data Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.48 1.89 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 49.32 49.06 49.93 Expected color at end point Choose... Choose... Choose... Volume of NaOH used (mL) 1. Average Volume of NaOH used in liters 2. Average moles of NaOH used (mol) 3. Average moles of acetic acid (mol)
Table 1. Titration data Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.48 1.89 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 49.32 49.06 49.93 Table 2. Titration data Table view List view Table 2. Titration data Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.48 1.89 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 49.32 49.06 49.93 Expected color at end point Choose... Choose... Choose... Volume of NaOH used (mL) 1. Average Volume of NaOH used in liters 2. Average moles of NaOH used (mol) 3. Average moles of acetic acid (mol)
Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.102E
Related questions
Question
Table 1. Titration data
Trial 1
|
Trial 2
|
Trial 3
|
|
---|---|---|---|
Initial burette reading (mL)
|
1.48
|
1.89
|
1.95
|
Molarity of NaOH (M)
|
0.100
|
0.100
|
0.100
|
Volume of vinegar sample (mL)
|
5.00
|
5.00
|
5.00
|
Final burette reading (mL)
|
49.32
|
49.06
|
49.93
|
Table 2. Titration data
Table view
List view
Table 2. Titration data
Trial 1
|
Trial 2
|
Trial 3
|
|
---|---|---|---|
Initial burette reading (mL)
|
1.48
|
1.89
|
1.95
|
Molarity of NaOH (M)
|
0.100
|
0.100
|
0.100
|
Volume of vinegar sample (mL)
|
5.00
|
5.00
|
5.00
|
Final burette reading (mL)
|
49.32
|
49.06
|
49.93
|
Expected color at end point
|
Choose...
|
Choose...
|
Choose...
|
Volume of NaOH used (mL)
|
|
|
1. Average Volume of NaOH used in liters
2. Average moles of NaOH used (mol)
3. Average moles of acetic acid (mol)
4. Average molarity of acetic acid (M)
5. Average mass of acetic acid (g)
6. Average mass of vinegar (g) (assume the density of vinegar is 1.00 g/mL)
7. Average mass % of acetic acid in vinegar
8. Known mass % of acetic acid in vinegar is 5.45%
Percent Error
9. Suppose the concentration of the NaOH solution was 0.5 M instead of 0.1 M. Would this titration have required more, less, or the same amount of NaOH solution for a complete reaction?
10. Suppose you used 0.5 M NaOH to titrate your vinegar sample instead of 0.1 M. What effect does the concentration of base added have on the reliability of the results of your titration?
11. Consider a 0.238 M aqueous solution of sodium hydroxide, NaOH.
a. How many grams of NaOH are dissolved in 23.46 mL?
b. How many individual hydroxide ions (OH−) are found in 23.46 mL?
c. How many moles of sulfuric acid, H2SO4, are neutralized by 23.46 mL of 0.238 M NaOH(aq)? [Hint: begin by writing a balanced equation for this neutralization reaction.]
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