The titration of 5.00 mL of 0.4949 M NH3 with 0.2250 M HNO3. Kb = 1.8×10–5. Fill out chart and list possible indicator. Volume HNO3 (mL) Calculated pH 1 initial 0.00 2 ¼ way to eq. point 3 ½ way to eq. point

The titration of 5.00 mL of 0.4949 M NH3 with 0.2250 M HNO3. Kb = 1.8×10–5. Fill out chart and list possible indicator. Volume HNO3 (mL) Calculated pH 1 initial 0.00 2 ¼ way to eq. point 3 ½ way to eq. point

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter8: Polyfunctional Acids And Bases

Section: Chapter Questions

Problem 10P

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Question

The titration of 5.00 mL of 0.4949 M NH₃ with 0.2250 M HNO₃. K_b = 1.8×10^–5. Fill out chart and list possible indicator.

		Volume HNO₃ (mL)	Calculated pH
1	initial	0.00
2	¼ way to eq. point
3	½ way to eq. point
4	¾ way to eq. point
5	0.5 mL before eq. point
6	equivalence point
7	0.5 mL after eq. point
8	well past eq. point	15.00

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