Save Answer Question 2 The ionization constant (Ka) equation of a monoportic weak, HA, acid is given by ca- K, = (1-a) The use of conductivity meter to test a 0.106 M solution of this weak acid gives a specific conductance, K, 20.24 µS.cm-1. What would be the pka, (-long Ka), of the acid, if its limiting molar ionic conductivities are y = 243 and A. = 74 S.cm2 mol"1 ? O A. 5.53 ОВ. 3.12 OC.6.00 OD.4.41 ОЕ 3.62

Fundamentals Of Analytical Chemistry
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ISBN:9781285640686
Author:Skoog
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Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.18QAP
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Question 2
The ionization constant (Ka) equation of a monoportic weak, HA, acid is given by
ca?
Ka =
(1–0)
The use of conductivity meter to test a 0.106 M solution of this weak acid gives a specific conductance, K, 20.24 µS.cm-1. What would be the pKa, (-long
Ka), of the acid, if its limiting molar ionic conductivities are d4 = 243 and . = 74 S.cm2 mol-1 ?
O A. 5.53
ОВ. 3.12
O C.6.00
O D. 4.41
O E. 3,62
Transcribed Image Text:Save Answer Question 2 The ionization constant (Ka) equation of a monoportic weak, HA, acid is given by ca? Ka = (1–0) The use of conductivity meter to test a 0.106 M solution of this weak acid gives a specific conductance, K, 20.24 µS.cm-1. What would be the pKa, (-long Ka), of the acid, if its limiting molar ionic conductivities are d4 = 243 and . = 74 S.cm2 mol-1 ? O A. 5.53 ОВ. 3.12 O C.6.00 O D. 4.41 O E. 3,62
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