Please send me the question in 20 minutes it's very urgent plz M3: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminmuy viving ivvivu Tivipici.Scientific Calculator (https://www.desmos.com/scientific)Periodic Table(https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_Equation Table(https://portagelearning.instructure.com/courses/948/files/271474/download?download_frd=1)Show the calculation of the volume of H₂O gas formed by the combustionof 18.6 grams of C6H6 at 30°C and 1.10 atm? The combustion ofbenzene (CH) takes place by the following reaction equation.2 C6H₁ (9) + 15 0₂ (9)12 CO2 (g) + 6H₂O (g)Your Answer:V = 5.377 Liters rounded to 5.38 LitersV = nRT/Pn = .2378 molesR= constant @ 0.0821T= 30°C +273 = 303 KP= 1.10 atmV = (.2378* 0.0821 * 303) / 1.10 atm = 5.377 Liters rounded to 5.38LitersMoles (n) of C6H6 = g/mW --> 18.6 / 78.108 = 2378 moles C6H₁MW (6 * 12.01) + (6 * 1.008) = 78.108 MW

Given: Mass of benzene = 18.6 g Pressure = 1.10 atm Temperature = 30oC = 273+30K=303 K Known: Molar…

Show the calculation of the volume of H₂O gas formed by the combustion of 18.6 grams of C6H6 at 30°C and 1.10 atm? The combustion of benzene (C6H₁) takes place by the following reaction equation. 2 C6H6 (g) + 15 O2 (g) 12 CO2 (g) + 6 H₂O (g)

Show the calculation of the volume of H₂O gas formed by the combustion of 18.6 grams of C6H6 at 30°C and 1.10 atm? The combustion of benzene (C6H₁) takes place by the following reaction equation. 2 C6H6 (g) + 15 O2 (g) 12 CO2 (g) + 6 H₂O (g)

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter5: Atomic Theory : The Nuclear Model Of The Atom

Section: Chapter Questions

Problem 50E

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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Please send me the question in 20 minutes it's very urgent plz

M3: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozmin
muy viving ivvivu Tivipici.
Scientific Calculator (https://www.desmos.com/scientific)
Periodic Table
(https://previous.nursingabc.com/upload/images/Help_file_picture/Periodic_
Equation Table
(https://portagelearning.instructure.com/courses/948/files/271474/download?
download_frd=1)
Show the calculation of the volume of H₂O gas formed by the combustion
of 18.6 grams of C6H6 at 30°C and 1.10 atm? The combustion of
benzene (CH) takes place by the following reaction equation.
2 C6H₁ (9) + 15 0₂ (9)
12 CO2 (g) + 6
H₂O (g)
Your Answer:
V = 5.377 Liters rounded to 5.38 Liters
V = nRT/P
n = .2378 moles
R= constant @ 0.0821
T= 30°C +273 = 303 K
P= 1.10 atm
V = (.2378* 0.0821 * 303) / 1.10 atm = 5.377 Liters rounded to 5.38
Liters
Moles (n) of C6H6 = g/mW --> 18.6 / 78.108 = 2378 moles C6H₁
MW (6 * 12.01) + (6 * 1.008) = 78.108 MW

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