Situation:Water is pumped from one tank to another. Find:r/d = 1, D1 = 10 in, L1 = 50 ft.f2 = 0.020, z1 = 10 ft.D2 = 10 in, L2 = 950 ft, f2 = 0.020.22 = 20 ft, T = 60°F.Discharge ( ft° / s).Properties:From Table 10.5: Ke= 0.03; K, = 0.35; KE = 1.0.Elevation = 20 ftL = 50 ftD = 10 inf = 0.020L = 950 ftD = 10 inf = 0.020rid = 1Elevation = 15 ftElevation = 10 ftT= 60°F8060* 40Pump curve201000 2000 3000 4000 5000Q, gpm

Since the pipe has constant area of cross section through out.…

Situation: Water is pumped from one tank to another. Find: r/d = 1, D = 10 in, L = 50 ft. f2 = 0.020, z1 = 10 ft. D2 = 10 in, L2 950 ft, fa = 0.020. z2 = 20 ft, T = 60°F. Discharge ( ft°/s). Properties: From Table 10.5: K. = 0.03; K, = 0.35; KE = 1.0. %3D %3D %3D

Situation: Water is pumped from one tank to another. Find: r/d = 1, D = 10 in, L = 50 ft. f2 = 0.020, z1 = 10 ft. D2 = 10 in, L2 950 ft, fa = 0.020. z2 = 20 ft, T = 60°F. Discharge ( ft°/s). Properties: From Table 10.5: K. = 0.03; K, = 0.35; KE = 1.0. %3D %3D %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Applied Fluid Mechanics

A fluid is a substance that is continuously deformed by the application of shear stress. The rate of deformation of a fluid depends on its viscosity. The fluid tries to flow when it interacts with some other system.

Question

Situation:
Water is pumped from one tank to another. Find:
r/d = 1, D1 = 10 in, L1 = 50 ft.
f2 = 0.020, z1 = 10 ft.
D2 = 10 in, L2 = 950 ft, f2 = 0.020.
22 = 20 ft, T = 60°F.
Discharge ( ft° / s).
Properties:
From Table 10.5: Ke
= 0.03; K, = 0.35; KE = 1.0.
Elevation = 20 ft
L = 50 ft
D = 10 in
f = 0.020
L = 950 ft
D = 10 in
f = 0.020
rid = 1
Elevation = 15 ft
Elevation = 10 ft
T= 60°F
80
60
* 40
Pump curve
20
1000 2000 3000 4000 5000
Q, gpm

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