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- Organic carbon in seawater can be measured by oxidation to CO2 with K2S2O8, followed by gravimetric determina- tion of CO2 trapped by a column of Ascarite. Water weighing 6.234 g produced 2.378 mg of CO2 (FM 44.010). Find ppm carbon in the seawater.Use this video to answer the questions: https://www.youtube.com/watch?v=BocfSXdbaU0A clinic had 25 patients on Friday morning. If 21 patientswere given flu shots, what percentage of the patientsreceived flu shots? Express your answer to the ones place.
- 7HelpHDPE and PS are both inert to bases and acids, which plastic would you rather chose to put 1 Liter of 6M HCl for general chemistry lab? Explain why.Please check my observations from the lab worksheet and watch the video. Accordingly, answer the questions . Link to lab Video: https://drive.google.com/file/d/1BR55ITa7wyOLgLy-MT6ogeXp-fiyuTHn/view?usp=sharing Link to calculated observations: https://drive.google.com/file/d/1zQ952X4N6hOgoToBF_o0zRARScwe54WH/view?usp=sharing Questions:
- 5.92 x 10^-15 ksp according to aleksYou are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed a competitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Km of the enzyme was found to be 1.5 x 10-5 M. What is the Ki of the inhibitor?Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…When drinking water is disinfected with chlorine, an undesired byproduct, chloroform (CHCl3), may form. Suppose a 70-kg person drinks 2 L of water every day for 70 years with a chloroform concentration of 0.08 mg/L (the drinking water standard). Potency factor for chloroform = 6.1 x 10-3 (mg/kg-day)-1 The upper-bound cancer risk for this individual. a. 0.545 b. 5.45x10-6 c. 5.45x10-4 d. 5.45x10-10 e. 14x10-6 If a city with 300,000 people in it also drinks the same amount water described in the above question, how many extra cancers per year would be expected? Assume the standard 70-year lifetime. a. 0.163 b. 1.63x10-4 c. 1.63x10-3 d. 1.63x10-6 e. 6x10-2