Sodium formate reacts with permanganate in neutral solution according to the equation CHO2 + MnO4 + H2O → MnO2(s) + CO2 + OH" (a) A 0.500 g sample containing sodium formate is treated with 50.00 mL of 0.0600 M MnO4 (an excess) in neutral solution, and the reaction given above is allowed to proceed to completion. The solution is filtered to remove the MnO2, acidified with H2SO4, and titrated with 30.00 mL of 0.1000 M H2C2O4. The MnO4- is reduced to Mn2+ and the oxalate oxidized to CO2. Calculate the percentage of NaCHO2 in the sample.

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